Chapter 11.3, Problem 52AYU

solve for x.

$\left[\begin{array}{l}\begin{array}{cc}x& 1\end{array}\\ \begin{array}{cc}3& x\end{array}\end{array}\right]=-2$

To determine

To find: The solution for $x$ where, $\left|\begin{array}{cc}x& 1\\ 3& x\end{array}\right|=-2$.

Answer to Problem 52AYU

$x=\pm 1$

Explanation of Solution

Given:

$\left|\begin{array}{cc}x& 1\\ 3& x\end{array}\right|=-2$

Calculation:

$\left|\begin{array}{cc}x& 1\\ 3& x\end{array}\right|=-2$

$x^2-3=-2$

$x^2=-2+3$

$x^2=1$

$x=\pm 1$