Based on the material covered in week 5 of the module, what conclusions can be drawn from the following data on the effect of compound Y on activity? Substrate Concentration (mM) Rate of enzyme catalysed reaction in the absence of compound Y (μmoles/min) Rate of enzyme catalysed reaction in the presence of compound Y (μmoles/min) 0.05 0.1 0.012 0.010 0.020 0.018 0.25 0.044 0.048 0.5 0.071 0.070 0.102 0.110 1 0.132 0.134 1.5 0.145 0.150 2 0.179 0.188 4 0.211 0.208 8 00 Use the editor to format your answer Last saved 09:47:24 Questions Filter (16) ▼ Search K First < Previous Next > Last > 果 Continue myhp

Based on the material covered in week 5 of the module, what conclusions can be drawn from the following data on the effect of compound Y on activity? Substrate Concentration (mM) Rate of enzyme catalysed reaction in the absence of compound Y (μmoles/min) Rate of enzyme catalysed reaction in the presence of compound Y (μmoles/min) 0.05 0.1 0.012 0.010 0.020 0.018 0.25 0.044 0.048 0.5 0.071 0.070 0.102 0.110 1 0.132 0.134 1.5 0.145 0.150 2 0.179 0.188 4 0.211 0.208 8 00 Use the editor to format your answer Last saved 09:47:24 Questions Filter (16) ▼ Search K First < Previous Next > Last > 果 Continue myhp

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Q22:
What enzyme kinetic parameters are apparantly impacted by uncompetitive inhibitors? Vmax Km Both Km and Vmax Neither Km nor Vmax
Below is kinetic data obtained for an enzyme-catalyzed reaction. The enzyme concentration is fixed at 100 nM. Using a Lineweaver-Burke plot, calculate the Vmax value for this reaction. Report your answer to four significant figures in units of uM/min.
Vmax and Km were calculated for enzyme substrate data. Results Y=0,0063x+0,3929 Km =62,4 mikromol/L Vm =159 mikromol/L.min But two additional data pairs were obtained at low concentrations and new graph equation Y=0,0063x+0,391 Recalculate Vmax and Km and compare and comment with previous results.
Practice Mira Gendy 1 of 1 Directions: This short free-response question requires about 6 minutes to answer. The question is worth 3 points. Read the question carefully and completely. Answers must be written out in paragraph form. Outlines, bulleted lists, or diagrams alone are not acceptable. II Substrate Concentration [S] The graph above shows the initial rate of an enzyme-catalyzed reaction at different substrate concentrations in the presence of a constant concentration of the enzyme. Connect the primary structure of the enzyme to its overall shape. I U x X2 5 Initial Rate of Reaction
An enzyme that follows simple Michaelis–Menten kinetics has an initial reaction velocity of 10 µmol⋅min-1 when the substrate concentration is five times greater than the KM. What is the Vmax of this enzyme in µmol⋅min−1?
The turnover number for an enzyme is known to be 5000min-1. Given the following set of data, Substrate concentration(mM) 1, 2, 4, 6, 100, 1,000 Initial Rate(micromol/min) 167, 250, 334, 376, 498, 499 a) What is the Km of the enzyme for the substrate? (do this without using a calculator) b) What is the total amount of enzyme present in the assay?
The following data were collected in the study of a new enzyme and an inhibitor of the new enzyme: Vo (nmol/sec) [S] (µM). 1.3 - Inhibitor + Inhibitor 2.50 0.62 2.6 4.00 1.42 6.5 6.30 2.65 13.0 7.60 3.12 26.0 9.00 3.58 What is the Vmax of the inhibited enzyme reaction?
Please do question 3) and explain
An enzyme catalyzes a reaction with a Km of 9.50 mM and a Vmax of 2.10 mM · s-1. Calculate the reaction velocity, vo, for each substrate concentration. [S] = 3.25 mM vo : mM · s-1 [S] = 9.50 mM mM · s-1 Vo :
Below is kinetic data obtained for an enzyme-catalyzed reaction. The enzyme concentration is fixed at 100 nM. Using a Lineweaver-Burke plot, calculate the kcat value for this reaction. Report your answer to three significant figures in units of 1/sec.
Answer the following questions, showing work in the form of calculations. a) At what substrate concentration would an enzyme with a Vmax of 102.5 M/min and a Km of 0.0025 M operate at one-quarter of its maximum rate? b) Determine the fraction of Vmax that would be obtained at the following substrate concentrations [S]: 0.5Km, 2Km, and 10Km.