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- The glucose/glucose-6-phosphate substrate cycle involves distinct reactions of glycolysis and gluconeogenesis that interconvert these two metabolites. Assume that under physiological conditions, [ATP] = [ADP]; [P;] = 1 mM. Consider the glycolytic reaction catalyzed by hexokinase: ATP + glucose ADP + glucose-6-phosphate AG = - 16.7 kJ/mol (a) Calculate the equilibrium constant (K) for this reaction at 298°K, and from that, calculate the maximum [glucose-6-phosphate]/ Iglucose] ratio that would exist under conditions where the reaction is still thermodynamically favorable. (b) Reversal of this interconversion in gluconeogenesis is catalyzed by glucose-6-phosphatase: glucose-6-phosphate + H20 = glucose + P AG" = -13.8 kJ/molThe enzyme aldolase catalyzes the reaction shown in the glycolytic pathway: Fructose 1,6-bisphosphate dihydroxyacetone phosphate + glyceraldehyde 3-phosphate The AG" for the reaction is +23.8 kJ mol¯¹ (+5.7 kcal mol−¹), whereas the AG in the cell is −1.3 kJ mol¯¹ (−0.3 kcal mol¯¹). Calculate the ratio of products to reactants under standard (equilibrium) conditions at 37°C. [products] [reactants] 7 x10-5 [products] [reactants] Incorrect Aldolase ===== Calculate the ratio of products to reactants under intracellular conditions at 37°C. 4 ×10-5 Incorrect Complete the statement using your results. under standard conditions under intracellular conditions A reaction that is endergonic under standard conditions can be converted into an exergonic reaction by maintaining the ratio of products to reactants below the equilibrium value.a) The following reaction which is catalyzed by aldolase: Fructose-,6-bisphosphate (FBP) + Glyceraldehyde 3-phosphate (GAP) + Dihydroxyacetone phosphate (DHAP) AG for this reaction is 22.8 kJ mol'. In the cell at 37°C, AG for this reaction is -5.9 kJ mol". Determine the ratio [GAP][DHAP]/[FBP]
- The glutamate dehydrogenase (GDH) catalyses the following reaction: *H₂N- H CH₂ CH₂ COO™ acide glutamique COO™ Time (min) A340 + NAD+ + H₂O The answer: GDH 2 1 1.760 1.718 [ammonium sulphate] = 0.33 M [NADH] = 0.205 mg.mL-¹ = 2.9.10-4 M [a-ketoglutarate] = 0.07 M [Protein] = 0.05 mg.mL-¹ COO™ CH₂ The activity of GDH is monitored in the sense of the formation of glutamate using the following conditions: 0.2 mL of 5 M ammonium sulphate 2.4 mL of buffer at pH 8 0.1 mL of NADH at 6.15 mg.mL-¹ (M = 709 g.mol-¹) 0.2 mL of 1 M a-ketoglutarate solution Warm mixture at 25 °C for 5 min Add 0.1 mL of GDH solution containing 1.6 mg.mL-¹protein to start the reaction. 5 3 4 1.675 1.635 1.595 !- Calculate ammonium sulphate, NADH, concentrations in the reaction medium at t = 0. CH₂ The change in absorbance at 340 nm is monitored, in a 1-cm cuvette, every minute for 10 min. Results are given in the table below: Data ENADH at 340 nm = 6220 M-¹.cm-¹ COO acide x-cétoglutarique O + NH4+ + NADH + H* 6 1.550…The ΔG°’ for the aldolase reaction of glycolysis in muscle is +22.8 kJ/mol. Why does the aldolase reaction proceed in the direction of glyceraldehyde-3-phosphate and dihydroxyacetone phosphate during glycolysis?A new drug, Proinebrium, that reduces Kcat (Ki = 2.0 uM) has been developed to treat ethylene glycol poisoning. (1) What concentration of Proinebrium is required to achieve 50% inhibition of ethylene glycol metabolism by alcohol dehydrogenase when the concentraion of ethlyene glycol in the blood is 50 uM?
- Proline racemase catalyzes the conversion between L-proline and D-proline. The Km and kcat for this reaction are 0.15 M and 550/sec respectively. If the enzyme concentration is 1.45 X 10-5 mmole/ml what is the Vmax of this reaction?What terms would best describe the above coupled reaction? (If the DGo for ATP hydrolysis into ADP + inorganic phosphate is -7.3 kcal/mole, and the DGo for maltose synthesis from glucose + glucose is +3.7 kcal/mole, calculate the standard free energy change for the combined reaction of ATP + glucose + glucose g ADP + maltose + inorganic phosphate.) it is non-spontaneous and endothermic (because the overall DGo is negative) it is spontaneous and exothermic (because the overall DGo is negative) it is non-spontaneous and endothermic (because the overall DGo is positive) it is spontaneous and exothermic (because the overall DGo is positive) it is non-spontaneous and exothermic (because the overall DGo is negative)Acetyl CoA + 2H* + 2e = pyruvate + COASH E = -0.48 V Ubiquinone + 2H* + 2e = Ubiquinol E" = +0.04 V Consider the redox rxn wherein a pair of e passes from pyruvate to ubiquinone. Calculate the change in standard Gibbs free energy (kJ/mol). Report answer to two decimal places.
- The glucose/glucose-6-phosphate substrate cycle involves distinct reactions of glycolysis and gluconcogenesis that interconvert these two metabolites. Assume that under physiological conditions, [ATP] = [ADP] and [Pi] =1 mM. Consider the following glycolytic reaction catalyzed by hexokinase: ATP + glucose = AG' = -16.7 kJ/mol ADP + glucose-6-phosphate (a) Calculate the equilibrium constant (K) for this reaction at 298 K, and from that, calculate the maximum [glucose-6-phosphate]/[glucose] ratio that would exist under conditions where the reaction is still thermody- namically favorable. (b) The reverse of this interconversion in gluconeogenesis is catalyzed by glucose-6-phosphatase: glucose-6-phosphate + H,0 = glucose + P, AGr = -13.8 kJ/mol K= 262 for this reaction. Calculate the maximum ratio of [glucose]/ [glucose-6-phosphate] that would exist under conditions where the reaction is still thermodynamically favorable. (c) Under what cellular conditions would both directions in the…The degradation of glycogen is catalyzed by the enzyme phosphorylase and has AGO" equal to +3.1 kJ · mol1. The equation for this reaction is shown below. glycogen (n residues) + P;→ glycogen (n-1 residues) + G1P What is the ratio of [P;]/[G1P] under standard conditions? Use 2 significant figures. [P;] : [G1P] = i :1 What is the value of AG under cellular conditions when the [P;/[G1P] ratio is 50/1? Use 2 significant figures. AG = i kJ. mol-1The standard free energy change for this reaction in the direction written is +23.8 kuimol. The tabie shows the concentrations of the three intermediates in the hepatocyte of a mammal. Intermediate Concentration (M) Fructose 1.0-bisphosphate 0.000028 Gyoeraldehyde 3phosphate 0.0000068 Ditydroxyacetone phosphate 0.000032 At body temperature (37 "C). what is the actual free energy change for the reaction (in kimol) ?