6. Examine the plot of the enzyme-catalyzed reaction below:Wheat-germ acid phosphatase shows Michaelis-Mentenkinetics when acting on para-nitrophenol phosphate161412108420.00.51.01.52.02.53.03.5(S] / mMa) Is this reaction better characterized by Michaelis-Menten kinetics or simple mass action?b) What is the approximate value of Vmax? Km?c) Assuming that this plot was made at 100 nM enzyme, draw the curve, including axis labels, for 300nM enzyme.d) Imagine that this enzyme is inhibited by a competitive inhibitor with Ki (for inhibitor) = Km (forsubstrate). Note that v = (kcat [E] tot [S]/Km) / (1 + [S]/Km + [I]/Ki). Draw the curve of reaction velocity(v) versus [S] for [I] = 1 mM.e) Now consider an experiment where you simultaneously introduce substrate and competitiveinhibitor at equal concentrations. Make a plot of v versus concentration of [S] = [I], i.e. the X-axisshould be the concentration of both I and S, which are equal.v/ uM min-

Enzyme kinetics is used to study the rates of enzyme catalysed biochemical reactions. We can observe…

Answered: a) Is this reaction better…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Based on the Lineweaver-Burke plot attached. Kinetic data were generated in the (1) absence of any inhibitor, (2) presence of 15 µM of a reversible inhibitor, or (3) presence of 20 µM of a second (distinct) reversible inhibitor. Purified enzyme concentration was 5 µM. The y-intercept of Lines (A) and (B) is 0.9 sec/uM; the y-intercept of Line (C) is 0.3 sec/uM. The slope of Line (A) is 1.8 sec; the slope of Lines (B) and (C) is 0.6 sec. Calculate the Vmax of the reaction represented by Line (C). Show all mathematical work, please.
Given the following reaction and equation for the initial velocity of the reaction: k₁ k3 E+S ES E + P V=Keat [ES] = k3 [ES] k₂ where keat is the rate constant for the reaction which forms the product from the ES complex. Explain in words why the velocity is directly proportional to theamount of enzyme added in the presence of saturating substrate levels.
If Vmax for a reaction is 10 μM ⋅ s-1 and the KM is 0.5 μM, what is the reaction velocity when the substrate concentration is 2 μM?
You are working on an enzyme that obeys standard Michaelis-Menten kinetics. What variable is the V, dependant on if the concentration of the substrate is substantially higher than the concentration of the enzyme? [S] [E] [ES] O [P] O not enough information provided
At what substrate concentration would an enzyme with a kcat of 33.0 s-1 and a Km of 0.0046 M operate at one-tenth of its maximum rate? Assume the enzyme obeys Michaeli s-Menten kinetics.
An enzyme with an unknown reaction mechanism has been isolated and is being investigated in the lab. Based on the information given below, propose one or more specific catalytic strategies (covalent, acid-base, and/or metal ion catalysis) used by the enzyme and predict the role of each catalytic residue in the enzyme's reaction cycle. Explain your reasoning. (a) Mapping of the active site with substrate analog showed that it contains a critical Ser residue. (b) Studies conducted in buffers of varying pH showed that the enzyme is sensitive to pH changes and has two catalytically important residues with pKa values of ~10.5 and ~4.0. (c) Substitution of the Ser residue with Ala resulted in a five-fold increase in the KM but had no effect on the kcat. (d) The reaction rate was insensitive to the addition of metal chelators such as EDTA and EGTA.
Based on the Lineweaver-Burke plot attached. Kinetic data were generated in the (1) absence of any inhibitor, (2) presence of 15 µM of a reversible inhibitor, or (3) presence of 20 µM of a second (distinct) reversible inhibitor. Purified enzyme concentration was 5 µM. The y-intercept of Lines (A) and (B) is 0.9 sec/uM; the y-intercept of Line (C) is 0.3 sec/uM. The slope of Line (A) is 1.8 sec; the slope of Lines (B) and (C) is 0.6 sec. Calculate the Km of the reaction represented by Line (B).
(i) Which graph indicates an enzymatic reaction without inhibitor?(ii) Which type of inhibitor is it? Briefly explain.(iii) Which graph indicates the highest concentration of inhibitor?(iv) Calculate the Vmax and Km of the graph showing an enzymatic reaction with the lowest concentration of inhibitor. Show the steps of calculation and unit in your answers. Keep 2 decimal places in your answers.
How is it possible to determine the structure of an enzyme substrate complex by x ray crystallography when the reaction is over so quickly and the x ray analysis takes at least several minutes?
there are A-D questions to this picture set up. A) What enzyme catalyzes this reaction? B) What is Delta G, please answer in Joules, K=19 C) If concentration of Glucose-1_Phosphate is 48.82 uM at equalibrium, what is the concentration of Glucose-6-phosphate in uM? D) If the reaction is NOT at equalibrium, what is delta G at 25C if the concentration of Glucose-1-phosphate is 15.04 uM and concentration of Glucose -6-phosphate is 1.62 mM? please answer in Joules and in significant figures. *note, 10^3uM in 1 mM Thank you!!
. The optimal conditions for salivary lysozyme (hydrolyzing glycoproteins of bacterial wall) are 37 C - temperature and pH is 5.2. Explain the decrease in this enzyme activity if the temperature will rise up to 60 °C and pH will be changed to 8.0. To answer the question: a) draw the graph of the velocity dependency on temperature and pH; b) calculate the relative enzyme activity if 10 mg of lysozyme catalyzes the formation of 5 uM of the product per 2 minutes. Concidor NH3: 5.
Enzyme X exhibits maximum activity at pH = 7.2. X shows a fairly sharp decrease in its activity when the pH goes much above 8.5. One likely interpretation of this observation is: ○ A) a key catalytic group has a pKa value that is shifted upward O B) an Asp residue on the enzyme is involved in the reaction O C) a Cys residue on the enzyme is involved in the reaction D) the enzyme active site is stabilized by a disulfide bridge ○ E) the reaction relies on specific acid-base catalysis

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