Given the following reaction and equation for the initial velocity of the reaction: k₁ k3 E+SES E + P V=Keat [ES] = k3 [ES] k₂ where keat is the rate constant for the reaction which forms the product from the ES complex. Explain in words why the velocity is directly proportional to theamount of enzyme added in the presence of saturating substrate levels.
Given the following reaction and equation for the initial velocity of the reaction: k₁ k3 E+SES E + P V=Keat [ES] = k3 [ES] k₂ where keat is the rate constant for the reaction which forms the product from the ES complex. Explain in words why the velocity is directly proportional to theamount of enzyme added in the presence of saturating substrate levels.
Biochemistry
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ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Rate defining step in a reaction
We are given two equations for initial velocity (V).
kcat is the the rate constant that describes the limiting rate of any enzyme catalyzed reaction at saturating substrate concentration. If one of the steps in the reaction mechanism is clearly the rate limiting step, then kcat becomes equal to the rate constant of that rate limiting step. This is the case that we see here. The rate limiting step in the reaction given is the conversion of ES to E and P. Hence, kcat = k3 .
We know that, the concentration of total enzyme added to the reaction mixture is equal to the sum of concentrations of free enzymes and the ES complex.
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