The following data were collected in the study of a new enzyme and an inhibitor of the new enzyme:
The following data were collected in the study of a new enzyme and an inhibitor of the new enzyme:
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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![### Enzyme Kinetics Study: Data Analysis
#### Study Background
The following data were collected in the study of a new enzyme and an inhibitor of the new enzyme:
#### Table: Initial Velocity (Vo) of Enzyme Reactions
This table provides the initial velocity (Vo) of the enzyme reactions both in the absence and presence of an inhibitor at varying substrate concentrations ([S]).
| [S] (μM) | Vo without Inhibitor (nmol/sec) | Vo with Inhibitor (nmol/sec) |
|----------|---------------------------------|------------------------------|
| 1.3 | 2.50 | 0.62 |
| 2.6 | 4.00 | 1.42 |
| 6.5 | 6.30 | 2.65 |
| 13.0 | 7.60 | 3.12 |
| 26.0 | 9.00 | 3.58 |
#### Analysis and Interpretation
The data indicates the difference in enzyme activity in the presence of an inhibitor. The initial velocity (Vo) is measured in nmol/sec, and substrate concentration ([S]) is measured in μM.
- **Without the inhibitor**: The initial velocities range from 2.50 nmol/sec at 1.3 μM substrate concentration to 9.00 nmol/sec at 26.0 μM substrate concentration.
- **With the inhibitor**: The initial velocities are significantly reduced, ranging from 0.62 nmol/sec at 1.3 μM substrate concentration to 3.58 nmol/sec at 26.0 μM substrate concentration.
#### Determining Vmax with Inhibitor
The question posed is: What is the \( V_{max} \) of the inhibited enzyme reaction?
To find the \( V_{max} \), particularly with the inhibitor present, the data suggest the maximum velocity approaches 3.58 nmol/sec as the substrate concentration increases to 26.0 μM. Therefore, based on the provided data:
- The \( V_{max} \) of the inhibited enzyme reaction is **3.58 nmol/sec**.
This dataset is crucial for understanding how the presence of an inhibitor affects the kinetics of an enzyme-catalyzed reaction.
---
For deeper insights, students can plot the data on a Michaelis-Menten](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F98834d82-84c5-4d71-9bf6-a3211e165794%2Feec6b577-b859-46ff-a666-805d67874e2d%2Fagqpafk_processed.png&w=3840&q=75)
Transcribed Image Text:### Enzyme Kinetics Study: Data Analysis
#### Study Background
The following data were collected in the study of a new enzyme and an inhibitor of the new enzyme:
#### Table: Initial Velocity (Vo) of Enzyme Reactions
This table provides the initial velocity (Vo) of the enzyme reactions both in the absence and presence of an inhibitor at varying substrate concentrations ([S]).
| [S] (μM) | Vo without Inhibitor (nmol/sec) | Vo with Inhibitor (nmol/sec) |
|----------|---------------------------------|------------------------------|
| 1.3 | 2.50 | 0.62 |
| 2.6 | 4.00 | 1.42 |
| 6.5 | 6.30 | 2.65 |
| 13.0 | 7.60 | 3.12 |
| 26.0 | 9.00 | 3.58 |
#### Analysis and Interpretation
The data indicates the difference in enzyme activity in the presence of an inhibitor. The initial velocity (Vo) is measured in nmol/sec, and substrate concentration ([S]) is measured in μM.
- **Without the inhibitor**: The initial velocities range from 2.50 nmol/sec at 1.3 μM substrate concentration to 9.00 nmol/sec at 26.0 μM substrate concentration.
- **With the inhibitor**: The initial velocities are significantly reduced, ranging from 0.62 nmol/sec at 1.3 μM substrate concentration to 3.58 nmol/sec at 26.0 μM substrate concentration.
#### Determining Vmax with Inhibitor
The question posed is: What is the \( V_{max} \) of the inhibited enzyme reaction?
To find the \( V_{max} \), particularly with the inhibitor present, the data suggest the maximum velocity approaches 3.58 nmol/sec as the substrate concentration increases to 26.0 μM. Therefore, based on the provided data:
- The \( V_{max} \) of the inhibited enzyme reaction is **3.58 nmol/sec**.
This dataset is crucial for understanding how the presence of an inhibitor affects the kinetics of an enzyme-catalyzed reaction.
---
For deeper insights, students can plot the data on a Michaelis-Menten
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