For an enzyme-catalyzed reaction, the velocity was determined at two different concentrations of the substrate. Estimate the value of \( V_{\text{max}} \).| [S] (mM) | V (nmol/min) ||----------|--------------|| 10 | 27 || 20 | 48 |Options:- ○ 88 nmol/min- ○ 79 nmol/min- ○ Not enough information is given to form a reasonable estimation.- ○ 67 nmol/min- ○ 51 nmol/min

The velocity of an enzyme catalyzed reaction is given by: V=Vmax×SKM+SWhere,V=velocity of the…

Answered: For an enzyme-catalyzed reaction, the…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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If 287.9 umol of enzyme X has a Vmax = 47.8 mmol/sec, what is the value of kcat %3D sec-1? Please report answer with 1 decimal place. Please do not report units. Your Answer: Answer units MacBook Air 888 F5 F4 F3 F2 %23 %24 %24
Calculate the slope on a Lineweaver-Burk plot (Km / Vmax) for the above enzyme (lactase). (enzyme lactase has a Vo of 0.111111111111 mM per minute when [S] = 1.0 mM, and a Vo of 0.20 mM per minute when [S] = 5.0 mM) 0.125 per minute 0.25 per minute 0.50 per minute 1.25 per minute 5.0 per minute
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KINETIC CONSTANT No Na2HPO4 25mM Na2HPO4 50mM Na2HPO4 Vmax nmol p-NP. Min- 20.3252 14.30615 17.30104 Km mM -0.819106 -0.46495 -0.352941 1. What does this suggest about the structure of the active side of the enzyme?
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82.16
The following data were obtained in a study of an enzyme known to follow Michaelis-Menten kinetics: Vo (micromol/min) Substrate added (mM) 200 1.0 400 2.0 800 4.0 1600 8.0 3200 16.0 The enzyme concentration used in all reactions is 106 M. Which of the following is true: O A) The Km for the reaction must be less than 1 mM ○ B) It is possible to determine Km for the reaction, but not Vmax or kcat OC) It is possible to determine only kcat, not Vmax or Km D) It is not possible to determine Vmax for the reaction OE) The ratio Vmax/Km for the reaction cannot be determined
What is the Vmax of an enzyme at 1 μM with -4G RT k = 6.2x 10¹2 s-1 (Ideal gas constant R = 8.314 J K-1 mol-1) cat 0.14 μM S-1 1.4 µM s-1 14 μM s-1 0.14 mM s-1 1.4 mM s-1 activation energy (AG) of 55000 J/mol at 298K?

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For an enzyme-catalyzed reaction, the velocity was determined at two different concentrations of the substrate. Estimate the value of Vmax. [S] (MM) 10 20 O 88 nmol/min 79 nmol/min 67 nmol/min V(nmol/min) 51 nmol/min 27 Not enough information is given to form a reasonable estimation. 48