41 The following data describe an enzyme-catalyzed reaction (hydrolysis ofcarbobenzoxyglycyl-L-tryptophan) Plot these results using the Lineweaver-Burkmethod, and determine values for KM and VmaxVelocity (mM.sec-)0 0240 0360 0530 0600 0610 062Substrate Concentration (mM)255010 015 020025 042 If the KM of an enzyme for its substrate remains constant as the concentration of theinhibitor increases, what can be said about the mode of inhibition and why?43 Calculate the turnover number for an enzyme, assumıng Vmax IS 05 M sec1 and theconcentration of the enzyme used is 0 002 M Why is it useful to know this?44 Dıscuss the mechanism of the Bohr effect that occurs during the interactions of Hbwith oxygen under physiological conditions in the lungs and tissues Make use ofrelevant graphs and diagrams to explain your answer

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Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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The following data were collected for an enzyme that can be described by Michaelis Menton kinetics. Use graphical analysis to determine the Km and Vmax for this exzyme / substrate combination. [S] mM Product formed (umol/min) 0.21 1.5 2.0 0.24 3.0 0.28 4.0 0.33 8.0 0.40 16.0 0.45
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The table below lists experimental conditions that can be applied to a reaction catalyzed by a hypothetical Michaelis–Menten enzyme. For each experimental condition described, complete the table to indicate as precisely as possible the effect (no change, half as large doubles, increases, decreases) on the maximal velocity, Vmax, and Michaelis constant, KM, of the hypothetical enzyme.
A purified protein sample was used in a reaction, resulting in an activity of 696.7 nmol min-1. The reaction volume was 145.0 µL and the final volume before loading the plate was 1,050 µL. The total reaction time was 4.25 min. The amount of protein used in the reaction was 4.270 µg. Calculate the specific activity of the sample (in nmol min-1 µg-1).
Vo 60 50 40 30 20 mm/sec 0100 0 O 0 0 50 100 150 200 250 300 Substrate (mM) Use the Michaelis-Menten plot to answer this question. What is the estimated value of Vmax of the enzyme catalyzed reaction (square data points)? (choose the one best answer) 10
If the enzyme lactase has a Vo of 0.40 mM per minute when [S] = 1.25 mM, and a Vo of 1.0 mM per minute when [S] = 5.0 mM, what is its Vmax? Calculate the Km of the above enzyme. Calculate the slope on a Lineweaver-Burk plot (Km / Vmax) for the above enzyme.
(b) You are investigating the effects of several agents on the activity of alcohol dehydrogenase. The enzyme activity data are shown in the table below. Construct a [substrate] vs. activity plot and a double-reciprocal plot for this enzyme. Be sure to label all axes. Determine the Vmax and KM for AD from the graphs in each type of plot. AD activity (nM/min) AD activity + agent A (nM/min) AD activity + agent B (nM/min) [Alcohol] (nM) 0.1 14 2 0.5 50 7 8. 1.0 65 10 30 2.0 72 12 45 4.0 80 14 62 8.0 85 15 75 32.0 90 16 90
If 287.9 umol of enzyme X has a Vmax = 47.8 mmol/sec, what is the value of kcat %3D sec-1? Please report answer with 1 decimal place. Please do not report units. Your Answer: Answer units MacBook Air 888 F5 F4 F3 F2 %23 %24 %24
Calculate the slope on a Lineweaver-Burk plot (Km / Vmax) for the above enzyme (lactase). (enzyme lactase has a Vo of 0.111111111111 mM per minute when [S] = 1.0 mM, and a Vo of 0.20 mM per minute when [S] = 5.0 mM) 0.125 per minute 0.25 per minute 0.50 per minute 1.25 per minute 5.0 per minute
Calculate the Km of the enzyme with these parameters. kcat = 130s^-1 Vo = 3.0 μMs-1 S = 10 μM Et = 0.09 µM
From a kinetics experiment, the Vmax was determined to be 450µM∙min-1. For the kinetic assay, 0.1mL of a 0.05mg/mL solution of enzyme was used, and the enzyme has a molecular weight of 125,000 g/mole. Assume a reaction volume of 700µL. Calculate the kcat (in sec-1) for the enzyme.
How do cytosolic NADH electrons get to the electron transport chain under aerobic conditions? My idea was that it used oxidation.

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