Operations Management
11th Edition
ISBN: 9780132921145
Author: Jay Heizer
Publisher: PEARSON
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Question
Chapter D, Problem 22P
a)
Summary Introduction
To determine: The minimum number of server for the system.
Introduction: The mathematical study which analyses the causes of delay in the waiting line is known as queuing theory. The theory examines all components in the waiting line such as arrival process, service process, and number of servers, system and customers.
b)
Summary Introduction
To determine: The optimal number of server for the system.
c)
Summary Introduction
To determine: The cost of the system at the usage of optimal number of servers.
d)
Summary Introduction
To determine: The server utilization rate at minimum number of server.
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Question related to queing theory don't copy
In a tool crib, workers come to take tools at 6 per hour on the average. Waiting for them
costs Rs. 12 per hour. The service time per worker is in the tool crib is 12 minutes. What
will be total waiting cost of the workers per day if it is 8 hours a day? Assume M/M/1 queuing
system.
Question 4
A petrol station in the capital Kingstown has a single pump manned by one attendant.
Vehicles arrive at the rate of 20 customers per hour and petrol filling takes 2 minutes on an
average. Assume the arrival rate is Poisson probability distribution and service rate is
exponentially distributed. Arrivals tend to follow a Poisson distribution, and service times
tend to be exponential. The attendant is paid $10 per hour, but because of lost goodwill and
sales, station loses about $15 per hour of customer time spent waiting for the attendant to
service and order.
Part A
Answer the following questions based on single channel model:
a. What is the probability that no customers are in the system (Po)?!
b. What is the average number of customers waiting for service (Lq)?
c. What is the average number of customers in the system (L)?…………..
d. What is the average time a customer waits for service (Wq)?!
e. What is the average time in the system (W)?❤❤
s
f. What is the probability that a…
Question 8.2
A fabric factory has 5 weaving machines in use. These weaving machines need repair after about 20
hours of use. Breakdowns have been determined to be Poisson distributed. Jim, the maintenance
worker can service a weaving machine in an average of 2 hours, following an exponential distribution.
Weaving machine downtime costs $120 per hour. Jim is paid $25 per hour.
a) What is the average time a weaving machine is waiting to be repaired?
b) What is the average number of weaving machines in the repairing area?
c) What is the total hourly costs?
Chapter D Solutions
Operations Management
Ch. D - Prob. 1DQCh. D - Prob. 2DQCh. D - Question 3. Name the three factors that govern the...Ch. D - Prob. 4DQCh. D - Prob. 5DQCh. D - Prob. 6DQCh. D - Prob. 7DQCh. D - Prob. 8DQCh. D - Prob. 9DQCh. D - Question 10. Describe the behavior of a waiting...
Ch. D - Question 11. Discuss 1he likely outcome of a...Ch. D - Prob. 12DQCh. D - Prob. 13DQCh. D - Prob. 14DQCh. D - Question 15. What happens if two single-server...Ch. D - Prob. 16DQCh. D - Prob. 17DQCh. D - Prob. 1PCh. D - Prob. 2PCh. D - Question D.3 Paul Fenster owns and manages a...Ch. D - Prob. 4PCh. D - Prob. 5PCh. D - Prob. 6PCh. D - Question D.7 Automobiles arrive at the...Ch. D - Question D.8 Virginias Ron McPherson Electronics...Ch. D - Question D.9 Neve Commercial Bank is the only...Ch. D - Question D.10 Beate Klingenberg manages a...Ch. D - Question D.11 Bill Youngdahl has been collecting...Ch. D - Question D.12 The wheat harvesting season in the...Ch. D - Prob. 13PCh. D - Prob. 14PCh. D - Prob. 15PCh. D - Prob. 16PCh. D - Prob. 17PCh. D - Prob. 18PCh. D - Question D.19 One mechanic services 5 drilling...Ch. D - Prob. 20PCh. D - Prob. 21PCh. D - Prob. 22PCh. D - Prob. 23PCh. D - Prob. 24PCh. D - Question New England Foundry For more than 75...Ch. D - Prob. 1.2CSCh. D - New England Foundry For more than 75 years, New...Ch. D - Question The Winter Park Hotel Lori Cook, manager...Ch. D - Question The Winter Park Hotel Lori Cook, manager...
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