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(a)
To find: The motion of the object with the mass and the damping factor.
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 32AYU
The direction of the bob is negative, the mass of the bob is
Explanation of Solution
Given:
The given covered by the bob is
Calculation:
Consider the given equation for distance is,
The bob is released from left to right it represents a negative direction and the motion described by the bob is damped.
Consider the general expression for the damped motion is,
From the given equation and from the above equation the amplitude of the displacement at
The value of
The damping factor is,
(b)
To find: The initial displacement of the bob.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 32AYU
The initial displacement is
Explanation of Solution
Given:
The given covered by the bob is
Calculation:
Consider the given equation for distance is,
From above the initial displacement of the bob is,
The initial displacement is
(c)
To find: The graph of the motion.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 32AYU
The required diagram is shown in Figure 1
Explanation of Solution
Given:
The given covered by the bob is
Calculation:
Consider the given equation for distance is,
By the use of MAPPLE, the graph of
Figure 1
(d)
To find: The displacement of the bob at the start of the second oscillation.
(d)
![Check Mark](/static/check-mark.png)
Answer to Problem 32AYU
Thestart of the second oscillation is approximately
Explanation of Solution
Given:
The given covered by the bob is
Calculation:
Consider the given equation for distance is,
From the graph shown in Figure 1, the displacement of the graph at the start of the second oscillation is approximately
(e)
To find: The displacement of the bob as the time increases without bound.
(e)
![Check Mark](/static/check-mark.png)
Answer to Problem 32AYU
The displacement of the bob as the time increases without bound reduces to zero.
Explanation of Solution
Given:
The given covered by the bob is
Calculation:
Consider the given equation for distance is,
From the graph is shown in Figure 1, as
Chapter 8 Solutions
Precalculus Enhanced with Graphing Utilities
Additional Math Textbook Solutions
Precalculus Enhanced with Graphing Utilities (7th Edition)
Glencoe Math Accelerated, Student Edition
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