The equation of the circle with centre at the point (−5,1) and radius is 3 and graph the circle.
Solution:
The equation of the circle with centre (−5,1) and radius 3 is (x+5)2+(y−1)2=9
To graph the equation, find some points satisfying the above circle equation.
x−2−5−8−5y141−2(x,y)(−2,1)(−5,4)(−8,1)(−5,−2)
Draw a circle using the above points
The graph of circle (x+5)2+(y−1)2=9 is
Given information:
Center of the circle is (−5,1) and radius is 3
The standard equation of circle with centre (h,k) and radius r is (x−h)2+(y−k)2=r2
Substitute the value of (h,k) as (−5,1) and r=3 in the above standard equation.
⇒(x−(−5))2+(y−1)2=32
⇒(x+5)2+(y−1)2=9
Therefore, the equation of the circle with centre (−5,1) and radius 3 is (x+5)2+(y−1)2=9
The graph of (x+5)2+(y−1)2=9 is
Precalculus Enhanced with Graphing Utilities
Precalculus
Thomas' Calculus: Early Transcendentals (14th Edition)
Calculus, Single Variable: Early Transcendentals (3rd Edition)
Glencoe Math Accelerated, Student Edition