Chapter 8.4, Problem 22AYU

To determine

To find: The area of the given triangle round to two decimal points.

Answer to Problem 22AYU

Solution:

$Area \approx 2.83$

Explanation of Solution

Given:

$a = 3, b = 3, c = 2$

Formula used:

$K = \sqrt{s \left(s - a\right) \left(s - b\right) \left(s - c\right)}$, where $s = \frac{a + b + c}{2}$

Calculation:

$a = 3, b = 3, c = 2$

Area of the triangle is given by

$K = \sqrt{s \left(s - a\right) \left(s - b\right) \left(s - c\right)}$, where $s = \frac{a + b + c}{2}$

$s = \frac{3 + 3 + 2}{2} = 4$

$K = \sqrt{4\left(4 - 3\right) \left(4 - 3\right) \left(4 - 2\right)}$

$K \approx 2.83$

$Area \approx 2.83$