Chapter 8.4, Problem 41AYU

To determine

To find: The ground area covered by the building.

Answer to Problem 41AYU

The area of the ground of the triangle is $7517.4{\text{ft}}^2$ .

Explanation of Solution

Given:

The given sides of the ground of the building is $87\text{ft}$ , $190\text{ft}$ andm:math>173 ft .

Calculation:

Consider the semi perimeter for the ground of the building is,

  $s=\frac{1}{2}\left(a+b+c\right)$

Then,

  $\begin{array}{c}s=\frac{1}{2}\left(87\text{ft}+190\text{ft}+173\text{ft}\right)\\ =225\text{ft}\end{array}$

Consider the formula for the area of the triangle is,

  $\begin{array}{c}K=\sqrt{225\text{ft}\left(225\text{ft}-87\text{ft}\right)\left(225\text{ft}-190\text{ft}\right)\left(225\text{ft}-173\text{ft}\right)}\\ =7517.4{\text{ft}}^2\end{array}$