Chapter 8.4, Problem 20AYU

To determine

To find: The area of the given triangle round to two decimal points.

Answer to Problem 20AYU

Solution:

$Area = 6$

Explanation of Solution

Given:

$a = 4, b = 5, c = 3$

Formula used:

$K = \sqrt{s \left(s - a\right) \left(s - b\right) \left(s - c\right)}$, where $s = \frac{a + b + c}{2}$

Calculation:

$a = 4, b = 5, c = 3$

Area of the triangle is given by

$K = \sqrt{s \left(s - a\right) \left(s - b\right) \left(s - c\right)}$, where $s = \frac{a + b + c}{2}$

$s = \frac{4 + 5 + 3}{2} = 6$

$K = \sqrt{6\left(6 - 4\right) \left(6 - 5\right) \left(6 - 3\right)}$

$K = 6$

$Area = 6$