Chapter 8, Problem 2STP

Interpretation Introduction

Interpretation:

The compound that contains at least one pi bond is to be predicted.

Concept introduction:

In the molecular formula, the element symbols and the subscripts number tells the type and the number of each atom in a molecule.

There are so many methods to represent a molecule. In ball-and-stick method, the atoms of each element are depicted by ball and the bond is depicted by stick. In structural formula method, the atoms of each element are depicted by letter symbols and bond is used to show relative position.

Answer to Problem 2STP

The compound that contains pi bond is ${\text{CO}}_{\text{2}}$. Therefore, option (A) is the correct option.

Explanation of Solution

Reason for correct option: The given compound is ${\text{CO}}_{\text{2}}$, ${\text{CHCl}}_{\text{3}}$, ${\text{AsI}}_{\text{3}}$, and ${\text{BeF}}_{\text{2}}$. The molecular structure of these compounds is shown below.

It is known that in single bond only sigma bond is present. In double bond, one bond is sigma and one is pi bond. In triple bond, one bond is sigma and the remaining two bonds are pi bond.

The representation of sigma and pi bonds in given compound ( ${\text{CO}}_{\text{2}}$, ${\text{CHCl}}_{\text{3}}$, ${\text{AsI}}_{\text{3}}$, and ${\text{BeF}}_{\text{2}}$ ) is shown below.

Therefore, only ${\text{CO}}_{\text{2}}$ has pi (p) bond. Therefore, option (A) is the correct option.

Conclusion

Reason for incorrect option: The ${\text{CHCl}}_{\text{3}}$ compound has no pi bond. So, B is incorrect option.

The ${\text{AsI}}_{\text{3}}$ compound has no pi bond. So, C is incorrect option.

The ${\text{BeF}}_{\text{2}}$ compound has no pi bond. So, D is incorrect option.