Chapter 8, Problem 144A

Interpretation Introduction

Interpretation:

The hybridization of atoms labeled as A, B, and C in the given figure is to be determined.

Concept introduction:

The combination of two things that have both the characteristic is termed as a hybrid. The process of mixing of atomic orbitals of different energy to form identical hybrid orbitals of equal energy is termed as hybridization.

Answer to Problem 144A

The hybridization of atoms labeled as A, B, and C in the figure is $s{p}^2$, $s{p}^3$, and $s{p}^2$ respectively.

Explanation of Solution

The given figure is shown below.

In the above ball and stick model, the black balls represent carbon atoms, red balls represent oxygen atoms, light blue balls represent nitrogen atoms, and dark blue balls represent hydrogen atoms. The molecular structure of luminol is shown below.

Here, the atom labeled as “a” is surrounded by three electron groups (One H atom and two carbon atoms). Therefore, the hybridization of an atom labeled as “a” is $s{p}^2$. The atom labeled as “b” is surrounded by four electron groups (One H atom, one carbon atom, one N atom, and one lone pair). Therefore, the hybridization of an atom labeled as “b” is $s{p}^3$. The atom labeled as “c” is surrounded by three electron groups (One C atom and two lone pairs). Therefore, the hybridization of an atom labeled as “c” is $s{p}^2$.

Conclusion

The hybridization of atoms labeled as A, B, and C in the given figure is $s{p}^2$, $s{p}^3$, and $s{p}^2$ respectively.