Interpretation:
Compare the estimated values with the experimental values have to be done.
Concept Introduction:
Atomic radius: The concept explain chemical element is a measured of the size of its atoms, in other words to measure the distance from the center of the nucleus to the boundary of the surrounding cloud of number of electrons.
Bond distance: In molecular geometry, bond length or bond distance is the average distance between nuclei of two bonded atoms in a molecule. It is a transferable property of a bond between atoms of fixed types, relatively independent of the rest of the molecule.
Increase and decrease electro negativity: The less vacancy electrons an atoms has the least it will gain of electrons. Moreover the
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Chemistry & Chemical Reactivity
- The bond length in HI(1.62) is close to the sum of the atomic radii of H (0.37 Å) and I (1.33 Å). What does this fact indicate about the polarity of the bond?arrow_forwardIf the dipole moment of a diatomic molecule is found to be 1.04 D, and its bond length is found to be 124 pm, what is the fractional charge on the atoms of the molecule in Coulombs (C)?arrow_forward"Inert" xenon actually forms several compounds, especially with the highly electronegative elements oxygen and fluorine. The simple fluorides XeF2, XeF4, and XeF, are all formed by direct reaction of the elements. As you might expect from the size of the xenon atom, the Xe-F bond is not a strong one. Calculate the Xe-F bond energy in XeF6, given that the heat of formation is -402 kJ/mol.arrow_forward
- “Inert” xenon actually forms several compounds, especially with the highly electronegative elements oxygen and fluorine. The simple fluorides XeF2, XeF4, and XeF6 are all formed by direct reaction of the elements. As you might expect from the size of the xenon atom, the Xe-F bond is not a strong one. Calculate the Xe-F bond energy in XeF6, given that the enthalpy of formation is - 402 kJ/mol.arrow_forwardBased on average bond enthalpies, would you expect a photon capable ofdissociating a C¬Cl bond to have sufficient energy to dissociate a C¬Br bond?arrow_forwardb) Answer the following question and give a brief explanation for your answers. a. Which one is more reactive : cesium, Cs or potassium, K? Explain b. Which one is more electronegative silicon, Si or tellurium, Te? Explain c. Arrange the following according to their size : smallest to largest. Justify your answer. O2 , F, Nearrow_forward
- Use the following data to estimate AH; for potassium bromide. K(s) + Br2 (9) - KBr(a) Lattice energy -671 kJ/mol Ionization energy for K 419 kJ/mol Electron affinity of Br -325 kJ/mol Bond energy of Br2 Enthalpy of sublimation for K 193 kJ/mol 90. kJ/mol AH = kJ/molarrow_forwardWhich is the bonding and which is the anti-bonding orbital? Describe the differences in these two orbitals with respect to the number of nodes present, the relative electron density located between the atoms versus that located outside the inter-nuclear region, and the overall size of regions with the same phase. How do you expect the wavelength of the electron to vary between these two orbitals? What about the relative energy of the electron in these two states? Explainarrow_forwardConsider the A2X4 molecule depicted here, where A and Xare elements. The A¬A bond length in this molecule is d1,and the four A¬X bond lengths are each d2. (a) In terms ofd1 and d2, how could you define the bonding atomic radii ofatoms A and X? (b) In terms of d1 and d2, what would you predictfor the X¬X bond length of an X2 molecule?arrow_forward
- Consider the A2X4 molecule depicted here, where A and Xare elements. The A¬A bond length in this molecule is d1,and the four A¬X bond lengths are each d2. (a) In terms ofd1 and d2, how could you define the bonding atomic radii ofatoms A and X? (b) In terms of d1 and d2, what would you predictfor the X¬X bond length of an X2 molecule? [Section 7.3]arrow_forwardIf an element is bonded to 4 other atoms and has a formal charge of +1, what group must the element be in? I know that group 3A atoms are elctron deficient, and that period 3 elements and below, except for group 3A elements like Aluminum, can expand their octet because of their available d-orbital, which may not be relevant to this problem. I don't understand this question, or why the answer would be 5A. Is it because 5A have odd valence electrons, and can form free radicals, like NO?arrow_forward2. Using the ionization energy of H 1s and CI 3p electrons of 13.6 eV and 13.1 eV, respectively, calculate the (a) energies and (b) compositions of the bonding and antibonding orbitals of HCI. (Use aH = -13.6 eV and acı = -13.1 eV.) Use B=-1.0 eV and S=0.arrow_forward
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