Interpretation:
The electronic configuration of Neodymium and the block of the periodic table in which it is located needs to be determined.
Concept introduction:
Electronic configuration of an element is the arrangement of elements in different orbitals like s, p, d, f. The filing of the electrons in the orbitals follow the Aufbau Principle.

Answer to Problem 55A
The electronic configuration of Neodymium is as follows:
It is located on the f-block.
Explanation of Solution
Aufbau principle should be followed while writing the electronic configuration of element. According to this rule lower energy level are filled first and then the higher energy levels.
Neodymium has electronic configuration1s22s2 2p6 3s2 3p6 4s2 3d104p6 5s2 4d10 5p66s2 4f4 and it is located in the f-block of the periodic table.
Chapter 6 Solutions
Chemistry: Matter and Change
Additional Science Textbook Solutions
Campbell Biology: Concepts & Connections (9th Edition)
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Cosmic Perspective Fundamentals
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Anatomy & Physiology (6th Edition)
Organic Chemistry (8th Edition)
- First I wanted to see if you would mind checking my graphs behind me. (They haven't been coming out right)? Second, could you help me explain if the rate of reaction is proportional to iodide and persulfate of each graph. I highlighted my answer and understanding but I'm not sure if I'm on the right track. Thank you in advance.arrow_forwardThe heat of combustion for ethane, C2H6C2H6 , is 47.8 kJ/g. How much heat is produced if 1.65 moles of ethane undergo complete combustion?arrow_forwardReview of this week's reaction: H2NCN (cyanamide) + CH3NHCH2COOH (sarcosine) + NaCl, NH4OH, H2O ----> H2NC(=NH)N(CH3)CH2COOH (creatine) Q7. Draw by hand the reaction of creatine synthesis listed above using line structures without showing the Cs and some of the Hs, but include the lone pairs of electrons wherever they apply. (4 pts) Q8. Considering the Zwitterion form of an amino acid, draw the Zwitterion form of Creatine. (2 pts) Q9. Explain with drawing why the C—N bond shown in creatine structure below can or cannot rotate. (3 pts)arrow_forward
- Would the following organic synthesis occur in one step? Add any missing products, required catalysts, inorganic reagents, and other important conditions. Please include a detailed explanation and drawings showing how the reaction may occur in one step.arrow_forwardPlease help me answer a. Please and thank you I advance.arrow_forwardDraw both of the chair flips for both the cis and trans isomers for the following compounds: 1,4-diethylcyclohexane 1-methyl-3-secbutylcyclohexanearrow_forward
- Ppplllleeeaaasssseeee hellppp wiithhh thisss physical chemistryyyyy I talked like this because AI is very annoyingarrow_forwardFor this question, if the product is racemic, input both enantiomers in the same Marvin editor. A) Input the number that corresponds to the reagent which when added to (E)-but-2-ene will result in a racemic product. Input 1 for Cl, in the cold and dark Input 2 for Oy followed by H₂O, Zn Input 3 for D₂ with metal catalyst Input 4 for H₂ with metal catalyst B) Draw the skeletal structure of the major organic product made from the reagent in part A Marvin JS Help Edit drawing C) Draw the skeletal structure of the major organic product formed when (2)-but-2-ene is treated with peroxyacetic acid. Marvin 35 Helparrow_forwardMichael Reactions 19.52 Draw the products from the following Michael addition reactions. 1. H&C CH (a) i 2. H₂O* (b) OEt (c) EtO H₂NEt (d) ΕΙΟ + 1. NaOEt 2. H₂O' H H 1. NaOEt 2. H₂O*arrow_forward
- Rank the labeled protons (Ha-Hd) in order of increasing acidity, starting with the least acidic. НОН НЬ OHd Онсarrow_forwardCan the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left? ? starting material target If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area. Be sure you follow the standard ALEKS rules for submitting syntheses. + More... Note for advanced students: you may assume that you are using a large excess of benzene as your starting material. C :0 T Add/Remove step Garrow_forwardThe following equations represent the formation of compound MX. What is the AH for the electron affinity of X (g)? X₂ (g) → 2X (g) M (s) → M (g) M (g) M (g) + e- AH = 60 kJ/mol AH = 22 kJ/mol X (g) + e-X (g) M* (g) +X (g) → MX (s) AH = 118 kJ/mol AH = ? AH = -190 kJ/mol AH = -100 kJ/mol a) -80 kJ b) -30 kJ c) -20 kJ d) 20 kJ e) 156 kJarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





