Chapter 6, Problem 3STP

Interpretation Introduction

Interpretation:

The group, period and block of an atom with the electronic configuration $[\text{Ar}]4s^{2}3d^{10}4p^4$ needs to be determined.

Concept introduction:

To determine the period from an electronic configuration, first identify the principal number from the electronic configuration. To identify the group, count the number of valence electrons and to identify the block, identify the orbital where valence electrons present.

Answer to Problem 3STP

The correct answer is C.

Explanation of Solution

The electronic configuration is $[\text{Ar}]4s^{2}3d^{10}4p^4$, which indicates that the highest occupied orbital is $4p$. So, principal number is 4 which indicate the period. Hence, period is 4.

Here, $4s^2$ and $4p^4$ indicates the valence electrons. Total 6 valence electrons present. So, the atom belongs to group 16 elements. So, group is 16.

The electrons in the p-orbital indicate that the outermost electrons are present in p-orbital. So, the element belongs to p-block.

Conclusion

The atom having electronic configuration $[\text{Ar}]4s^{2}3d^{10}4p^4$ present in 4^th period and group 16. Also the element belongs to p-block.