Chapter 6, Problem 38A

Interpretation Introduction

Interpretation:

The group and period of the element with 117 protons needs to be determined. Whether it is a metal, non-metal or a metalloid needs to be determined.

Concept introduction:

In the periodic table, vertical rows are termed as groups and horizontal rows are termed as periods. There are 18 groups and 7 periods in the periodic table. From the electronic configuration of the element, its group and period can be known.

Answer to Problem 38A

The period and group to which element of atomic number 117 belong is 7 and 17 respectively and it is metalloid.

Explanation of Solution

The element contains 117 protons that mean atomic number of the element is 117. So, electronic configuration of the element is $[\text{Rn}]5f^{14}6d^{10}7s^{2}7p^5$. From the electronic configuration it is clear that principal number is 7. Principal number indicates the period of the element. So, Period in which the element is present is 7. The number of valence electrons in the element is 7. So, the group in which the element presents is group 17.

Conclusion

Element of atomic number 117 belongs to 7^th period and 17 group and it is a metalloid.