Concept explainers
(a)
Interpretation:
The more stable compound from the given set of compounds should be determined.
Concept introduction:
Carbocation: It is carbon ion that bears a positive charge on it.
Leaving group: It is a fragment that leaves from a substrate with a pair of electrons via
Carbocation stability order:
Resonance stabilization: Due to the delocalization of electrons within the molecule the overall energy becomes lower and makes that molecule more stable.
Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.
Nucleophilic nature depends on the negative charge present in the molecule, the solvent in which it present and the electronegativity of the atom.
Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.
(b)
Interpretation:
The more stable compound from the given set of compounds should be determined.
Concept introduction:
Carbocation: It is carbon ion that bears a positive charge on it.
Leaving group: It is a fragment that leaves from a substrate with a pair of electrons via
Carbocation stability order:
Resonance stabilization: Due to the delocalization of electrons within the molecule the overall energy becomes lower and makes that molecule more stable.
Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.
Nucleophilic nature depends on the negative charge present in the molecule, the solvent in which it present and the electronegativity of the atom.
Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.
(c)
Interpretation:
The more stable compound from the given set of compounds should be determined.
Concept introduction:
Carbocation: It is carbon ion that bears a positive charge on it.
Leaving group: It is a fragment that leaves from a substrate with a pair of electrons via
Carbocation stability order:
Resonance stabilization: Due to the delocalization of electrons within the molecule the overall energy becomes lower and makes that molecule more stable.
Nucleophile: Nucleophiles are electron rich compounds which donates electrons to electrophilic compounds which results in bond formation.
Nucleophilic nature depends on the negative charge present in the molecule, the solvent in which it present and the electronegativity of the atom.
Electrophile: Electrophiles are electron deficient compounds which accepts electrons from nucleophiles that results in bond formation.
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Check out a sample textbook solutionChapter 6 Solutions
Essential Organic Chemistry, Global Edition
- Draw the alkene that would react with the reagent given to account for the product formed. ? + HCI CH3 CH3CCH3 CI • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. #[ ] در ChemDoodlearrow_forwardWhat is the productarrow_forwards sugar X a reducing or a non-reducing sugar? Reducing, because one/both of the rings can open to expose a free aldehyde group Non-reducing, because one/both of the rings can open to expose a free aldehyde group Reducing, because neither of the rings can open to expose a free aldehyde group Non-reducing, because neither of the rings can open to expose a free aldehyde group Reducing, because one/both of the rings can open to expose a free ketone group Non-reducing, because one/both of the rings can open to expose a free ketone group Reducing, because neither of the rings can open to expose a free ketone group Non-reducing, because neither of the rings can open to expose a free ketone group Cannot be determined from the structure shownarrow_forward
- Draw the alkene that would react with the reagent given to account for the product formed. ? + + H₂O **** H₂S04 • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. CH3 CH3 CHCCH3 | | OH CH3 +1arrow_forward22 J Which one of the following alkenes is the most stable? H3C CH3 H3C CH3 H3C CH2-CH3 ÇH3 C=C H3C CH2 =CH2 H3C CH3 H3C H. IV I II II A O .B || .C O II DOarrow_forwardDraw the organic product of the following reaction. CH3 m-CICgH,CO;H • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • If the reaction produces a racemic mixture, just draw one stereoisomer. • If more than one product is possible, only draw the major product. opy astearrow_forward
- Draw the most stable resonance form for the intermediate in the following electrophilic substitution reaction. CI CI HNO3 / H2SO4 O2N You do not have to consider stereochemistry. • Include all valence lone pairs in your answer. • In cases where there is more than one answer, just draw one.arrow_forwardWhat is more stable acetate (CH3COO-) or ethoxide (CH3CH2O-)? In three words or less explain your choice:arrow_forwardIdentify the alkene that is the most stable and the alkene that is the least stable. Most stable = Explanation for most stable carbocation: 11 ; Least stable = IIIarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning