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Shock Absorber When a car hits a certain bump on the road, a shock absorber on the car is compressed a distance of 6 in., then released (see the figure). The shock absorber vibrates in damped harmonic motion with a frequency of 2 cycles per second. The damping constant for this particular shock absorber is 2.8.
- (a) Find an equation that describes the displacement of the shock absorber from its rest position as a function of time. Take t = 0 to be the instant that the shock absorber is released.
- (b) How long does it take for the amplitude of the vibration to decrease to 0.5 in.?
(a)
![Check Mark](/static/check-mark.png)
The equation which models the displacement of the shock absorber as a function of time.
Answer to Problem 46E
The equation for the displacement of the shock absorber as a function of time
is
Explanation of Solution
Given:
The frequency of the shock absorber is
Definition used:
The equation for the damped harmonic motion which describes the displacement y of an object at time t is,
Calculation:
Calculate the equation for the displacement of the shock absorber from it’s rests position.
Assume
The formula to calculate the value of
Substitute the value 2 for f in the above formula.
The value of
Substitute the value 6 for k,
Hence, the function for the displacement is
(b)
![Check Mark](/static/check-mark.png)
The time for the amplitude of the vibration to decrease to
Answer to Problem 46E
The time for the amplitude of the vibration to decrease to
Explanation of Solution
Given:
The damping constant c is
Definition used:
The equation for the damped harmonic motion which describes the displacement y of an object at time t is,
Calculation:
Calculate the time for the amplitude of the vibration to decrease to 0.5 in.
The general equation for the harmonic motion is,
Compare equation (1) and (2),
Substitute the value 6 for k,
Further solve the value of equation,
Solve the value of t,
Thus, the value of the time for the amplitude is
Chapter 5 Solutions
Precalculus: Mathematics for Calculus - 6th Edition
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