3 Given the 4-periodic function f(x), coinciding for x = [−2, 2] with the function (x) = 1 if |x| € [0, 1] and with the function x(x) = |x| if |x| € (1,2]. The Fourier series of f: (A) is in the form 5 + 5 (B) is in the form 5 (C) is in the form ∞ IM: IM k=1 ∞ (ak cos(kx) + bk sin(kx), ak 0, bk 0 ak cos(kx), ak 0, kπx ak Cos , ak 0, k=1 (D) is not pointwise converging f(x) for every x Є R
3 Given the 4-periodic function f(x), coinciding for x = [−2, 2] with the function (x) = 1 if |x| € [0, 1] and with the function x(x) = |x| if |x| € (1,2]. The Fourier series of f: (A) is in the form 5 + 5 (B) is in the form 5 (C) is in the form ∞ IM: IM k=1 ∞ (ak cos(kx) + bk sin(kx), ak 0, bk 0 ak cos(kx), ak 0, kπx ak Cos , ak 0, k=1 (D) is not pointwise converging f(x) for every x Є R
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.5: Properties Of Logarithms
Problem 67E
Related questions
Question
The correct answer is C
could you show me how to do it by finding a0 and and ak
as well as setting up the
![3 Given the 4-periodic function f(x), coinciding for x = [−2, 2] with the function (x) = 1
if |x| € [0, 1] and with the function x(x) = |x| if |x| € (1,2]. The Fourier series of f:
(A) is in the form
5
+
5
(B) is in the form
5
(C) is in the form
∞
IM: IM
k=1
∞
(ak cos(kx) + bk sin(kx), ak 0, bk 0
ak cos(kx), ak 0,
kπx
ak Cos
, ak 0,
k=1
(D) is not pointwise converging f(x) for every x Є R](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6099d21a-e15a-47f8-adbb-0c871c33581f%2Fcaa94bdf-f2c6-44d0-b4c0-6b5db977546d%2Fm60dd8h_processed.png&w=3840&q=75)
Transcribed Image Text:3 Given the 4-periodic function f(x), coinciding for x = [−2, 2] with the function (x) = 1
if |x| € [0, 1] and with the function x(x) = |x| if |x| € (1,2]. The Fourier series of f:
(A) is in the form
5
+
5
(B) is in the form
5
(C) is in the form
∞
IM: IM
k=1
∞
(ak cos(kx) + bk sin(kx), ak 0, bk 0
ak cos(kx), ak 0,
kπx
ak Cos
, ak 0,
k=1
(D) is not pointwise converging f(x) for every x Є R
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