The point P in the figure at the left has y-coordinate
- (a) sin t
- (b) cos t
- (c) tan t
- (d) sec t
(a)
To find: The value for sin t.
Answer to Problem 2T
The value of sin t is
Explanation of Solution
Given:
The value of point y is,
Calculation:
The trigonometric functions of the terminal point on the unit circle is shown as,
Substitute
Since point P lies in quadrant II, therefore sin t is positive.
Hence, the value of sin t is
(b)
To find: The value for cost.
Answer to Problem 2T
The value of cost is
Explanation of Solution
Given:
The value of point y is,
Formula Used:
The equation of unit circle with radius 1 centered at origin is,
Calculation:
The trigonometric functions of the terminal point on the unit circle is shown as,
Use formula of unit circle to find the value of x.
Substitute
Simplify the above equation,
Substitute cost for x in the above equation,
Since point P lies in quadrant II, therefore cost is negative.
Hence, the value of cost is
(c)
To find: The value for tan t.
Answer to Problem 2T
The value of tan t is
Explanation of Solution
Given:
The value of point y is,
Calculation:
The trigonometric functions of the terminal point on the unit circle is shown as,
Substitute
Since point P lies in quadrant II, therefore tan t is negative.
Hence, the value of tan t is
(d)
To find: The value for sec t.
Answer to Problem 2T
The value of sec t is
Explanation of Solution
Given:
The value of point y is,
Calculation:
The trigonometric functions of the terminal point on the unit circle is shown as,
Substitute
Since point P lies in quadrant II, therefore sec t is negative.
Hence, the value of sec t is
Chapter 5 Solutions
Precalculus: Mathematics for Calculus - 6th Edition
- 4c Consider the function f(x) = 10x + 4x5 - 4x³- 1. Enter the general antiderivative of f(x)arrow_forwardA tank contains 60 kg of salt and 2000 L of water. Pure water enters a tank at the rate 8 L/min. The solution is mixed and drains from the tank at the rate 11 L/min. Let y be the number of kg of salt in the tank after t minutes. The differential equation for this situation would be: dy dt y(0) =arrow_forwardSolve the initial value problem: y= 0.05y + 5 y(0) = 100 y(t) =arrow_forward
- y=f'(x) 1 8 The function f is defined on the closed interval [0,8]. The graph of its derivative f' is shown above. How many relative minima are there for f(x)? O 2 6 4 00arrow_forward60! 5!.7!.15!.33!arrow_forward• • Let > be a potential for the vector field F = (−2 y³, −6 xy² − 4 z³, −12 yz² + 4 2). Then the value of sin((-1.63, 2.06, 0.57) – (0,0,0)) is - 0.336 -0.931 -0.587 0.440 0.902 0.607 -0.609 0.146arrow_forward
- The value of cos(4M) where M is the magnitude of the vector field with potential ƒ = e² sin(лy) cos(π²) at x = 1, y = 1/4, z = 1/3 is 0.602 -0.323 0.712 -0.816 0.781 0.102 0.075 0.013arrow_forwardThere is exactly number a and one number b such that the vector field F = conservative. For those values of a and b, the value of cos(a) + sin(b) is (3ay + z, 3ayz + 3x, −by² + x) is -0.961 -0.772 -1.645 0.057 -0.961 1.764 -0.457 0.201arrow_forwardA: Tan Latitude / Tan P A = Tan 04° 30'/ Tan 77° 50.3' A= 0.016960 803 S CA named opposite to latitude, except when hour angle between 090° and 270°) B: Tan Declination | Sin P B Tan 052° 42.1'/ Sin 77° 50.3' B = 1.34 2905601 SCB is alway named same as declination) C = A + B = 1.35 9866404 S CC correction, A+/- B: if A and B have same name - add, If different name- subtract) = Tan Azimuth 1/Ccx cos Latitude) Tan Azimuth = 0.737640253 Azimuth = S 36.4° E CAzimuth takes combined name of C correction and Hour Angle - If LHA is between 0° and 180°, it is named "west", if LHA is between 180° and 360° it is named "east" True Azimuth= 143.6° Compass Azimuth = 145.0° Compass Error = 1.4° West Variation 4.0 East Deviation: 5.4 Westarrow_forward
- ds 5. Find a solution to this initial value problem: 3t2, s(0) = 5. dt 6. Find a solution to this initial value problem: A' = 0.03A, A(0) = 100.arrow_forward2) Drive the frequency responses of the following rotor system with Non-Symmetric Stator. The system contains both external and internal damping. Show that the system loses the reciprocity property.arrow_forward1) Show that the force response of a MDOF system with general damping can be written as: X liax) -Σ = ral iw-s, + {0} iw-s,arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning