
a.
Define the function along with its range and domain.
a.

Answer to Problem 9RCC
Explanation of Solution
Calculation:
Here, sine function is not one-to-one function. To make it so we have to restrict its domain to one period.
Now, we will choose the interval
Now, here the range of restricted function
Thus, from this we will define the inverse sine function as:
We know that the domain and range of an inverse function are reversed, so the domain of the function becomes the range of its inverse and its range becomes the domain of the inverse.
Hence, the domain
b.
Find if the equation is true or not.
b.

Answer to Problem 9RCC
It is true.
Explanation of Solution
Calculation:
Here, we know the cancellation property of an inverse function.
Hence,
c.
Find if the equation is true or not.
c.

Answer to Problem 9RCC
It is true.
Explanation of Solution
Calculation:
Here, we know the cancellation property of an inverse function.
Hence,
Chapter 5 Solutions
Precalculus: Mathematics for Calculus - 6th Edition
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- Find the indefinite integral. Check Answer: 7x 4 + 1x dxarrow_forwardHere is a region R in Quadrant I. y 2.0 T 1.5 1.0 0.5 0.0 + 55 0.0 0.5 1.0 1.5 2.0 X It is bounded by y = x¹/3, y = 1, and x = 0. We want to evaluate this double integral. ONLY ONE order of integration will work. Good luck! The dA =???arrow_forward43–46. Directions of change Consider the following functions f and points P. Sketch the xy-plane showing P and the level curve through P. Indicate (as in Figure 15.52) the directions of maximum increase, maximum decrease, and no change for f. ■ 45. f(x, y) = x² + xy + y² + 7; P(−3, 3)arrow_forward
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