Chapter 5.3, Problem 2E

To determine

To calculate; the amplitude and the period.

Answer to Problem 2E

  $amplitude=3$

  $period=\frac{2\pi }{2}=\pi$

Explanation of Solution

The amplitude of $a\sin x$

  $\text{= a for a > 0}$ . In the given case $a=3$ , therefore, $amplitude=3$

The period of $\sin bx$ is $\frac{2\pi }{b},b>0$ . In the given case $b=2$ , therefore, $period=\frac{2\pi }{2}=\pi$