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(a)
To find: The speed of the rock just before it hits the ground just before it hits the bottom 30 sec later when the acceleration due to the gravity is
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 43E
The value of the speed is
Explanation of Solution
Calculation:
Consider the acceleration is,
Consider the velocity is the anti-derivative of the acceleration that is,
Then,
(b)
To find: The distance below the point of the release is the bottom of the crevasse.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 43E
The distance is of
Explanation of Solution
Calculation:
Consider the expression for the distance is,
Then, after 30 sec is,
(c)
To find: The time at which the rock will hit the bottom and the speed at which the rock will go.
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 43E
The required time is
Explanation of Solution
Given:
The rock instead of being released from the rest the rock is thrown into the crevasse from the same point with the downward velocity of
Calculation:
Consider the velocity is the anti-derivative of the acceleration that is,
Then,
Then, the equation is,
Then, the distance travelled is,
Then,
Then, the velocity is,
Chapter 5 Solutions
Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)
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Algebra and Trigonometry (6th Edition)
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