a. Answer The absolute maximum is 3 at x = 3 and the absolute maximum is − 2 at x = 1 Explanation Calculation: From the Given graph, critical values are x = 0 and x = 3 , which are nay values of x that make f ′ ( x ) = 0 or undefined. From the table, f ′ ( 1 ) = 0 and f ′ ( 2 ) undefined. So critical values are x = 1 and x = 2 From the table, f ( 0 ) = 0 , f ( 1 ) = − 2 , f ( 2 ) = 0 , f ( 3 ) = 3 Thus the absolute maximum is 3 at x = 3 and the absolute maximum is − 2 at x = 1 b. To determine From the given table, find the inflection points. Answer From the table, there are no points of inflection because f is concave up f ′ ′ > 0 through out the interval. Explanation Calculation: From the table, there are no points of inflection because f is concave up f ′ ′ > 0 through out the interval. c. To determine Sketch the graph. Answer Explanation Calculation: Graph of the function as shown below:

Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

4th Edition

ISBN: 9780133178579

Author: Ross L. Finney

Publisher: PEARSON

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Concept explainers

Rate of Change

The relation between two quantities which displays how much greater one quantity is than another is called ratio.

Slope

The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as:

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Question

Chapter 5, Problem 36RE

To determine

From the given table, find the absolute maximum.

Expert Solution

Answer to Problem 36RE

The absolute maximum is 3 at x=3 and the absolute maximum is −2 at x=1

Explanation of Solution

Calculation:

From the Given graph, critical values are x=0 and x=3, which are nay values of x that make f′(x)=0 or undefined.

From the table, f′(1)=0 and f′(2) undefined.

So critical values are x=1 and x=2

From the table, f(0)=0,f(1)=−2,f(2)=0,f(3)=3

Thus the absolute maximum is 3 at x=3 and the absolute maximum is −2 at x=1

To determine

From the given table, find the inflection points.

Expert Solution

Answer to Problem 36RE

From the table, there are no points of inflection because f is concave up f′′>0 through out the interval.

Explanation of Solution

Calculation:

From the table, there are no points of inflection because f is concave up f′′>0 through out the interval.

To determine

Sketch the graph.

Expert Solution

Answer to Problem 36RE

Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 5, Problem 36RE , additional homework tip 1

Explanation of Solution

Calculation:

Graph of the function as shown below:

Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 5, Problem 36RE , additional homework tip 2

Chapter 5, Problem 35RE

Chapter 5, Problem 37RE

Chapter 5 Solutions

Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

Ch. 5.1 - Prob. 1QR Ch. 5.1 - Prob. 2QR Ch. 5.1 - Prob. 3QR Ch. 5.1 - Prob. 4QR Ch. 5.1 - Prob. 5QR Ch. 5.1 - Prob. 6QR Ch. 5.1 - Prob. 7QR Ch. 5.1 - Prob. 8QR Ch. 5.1 - Prob. 9QR Ch. 5.1 - Prob. 10QR

Ch. 5.1 - Prob. 11QR Ch. 5.1 - Prob. 12QR Ch. 5.1 - Prob. 1E Ch. 5.1 - Prob. 2E Ch. 5.1 - Prob. 3E Ch. 5.1 - Prob. 4E Ch. 5.1 - Prob. 5E Ch. 5.1 - Prob. 6E Ch. 5.1 - Prob. 7E Ch. 5.1 - Prob. 8E Ch. 5.1 - Prob. 9E Ch. 5.1 - Prob. 10E Ch. 5.1 - Prob. 11E Ch. 5.1 - Prob. 12E Ch. 5.1 - Prob. 13E Ch. 5.1 - Prob. 14E Ch. 5.1 - Prob. 15E Ch. 5.1 - Prob. 16E Ch. 5.1 - Prob. 17E Ch. 5.1 - Prob. 18E Ch. 5.1 - Prob. 19E Ch. 5.1 - Prob. 20E Ch. 5.1 - Prob. 21E Ch. 5.1 - Prob. 22E Ch. 5.1 - Prob. 23E Ch. 5.1 - Prob. 24E Ch. 5.1 - Prob. 25E Ch. 5.1 - Prob. 26E Ch. 5.1 - Prob. 27E Ch. 5.1 - Prob. 28E Ch. 5.1 - Prob. 29E Ch. 5.1 - Prob. 30E Ch. 5.1 - Prob. 31E Ch. 5.1 - Prob. 32E Ch. 5.1 - Prob. 33E Ch. 5.1 - Prob. 34E Ch. 5.1 - Prob. 35E Ch. 5.1 - Prob. 36E Ch. 5.1 - Prob. 37E Ch. 5.1 - Prob. 38E Ch. 5.1 - Prob. 39E Ch. 5.1 - Prob. 40E Ch. 5.1 - Prob. 41E Ch. 5.1 - Prob. 42E Ch. 5.1 - Prob. 43E Ch. 5.1 - Prob. 44E Ch. 5.1 - Prob. 45E Ch. 5.1 - Prob. 46E Ch. 5.1 - Prob. 47E Ch. 5.1 - Prob. 48E Ch. 5.1 - 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