The boss in your laboratory has just heard of a proposal by another laboratory that genes for eye color and the length of body bristles may be linked in Drosophila. Your lab has numerous pure-breeding stocks of Drosophila that could be used to verify of refute genetic linkage. In Drosophila, red eyes
a. Give the genotypes of the pure-breeding parental-files, and the genotype
b. In your experimental design, what are the genotype and phenotype of the line you propose to cross to the F1 to obtain the most useful information about genetic linkage between the eye color and bristle-length genes? Explain why you make this choice.
c. Assume the eye color and bristle-length genes are separated by
d. How would the results of the cross differ if the genes are not linked?
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Genetic Analysis: An Integrated Approach (3rd Edition)
- Please explainarrow_forwardDrosophila can have a yellow-brown body (wild-type [+]) or a black body [b] as a result of a mutation in the black gene (marked b). a mutation in the black gene (marked b). There is also a mutation in the purple gene (marked pr) which purple eyes (mutant phenotype [pr]). Flies with normal eyes are noted [+]. a/ Pure strains of male Drosophila [b] are crossed with female Drosophila [pr] (1st cross). The F1 progeny contains only wild-type Drosophila for the two [+, +] traits. both [+, +] traits. The reciprocal cross gives the same result. F1 females from the first cross are crossed with [b, pr] double mutant males. The progeny is composed of : 944 [b, +] 936 [+, pr] 56 [+, +] 64 [b, pr] How do you explain this segregation? How many percentage recombinationarrow_forwarda) What gene is in the middle? b) Calculate the genetic distances (in centimorgans, cM) between: genes b and cn: genes cn and wx: genes b and wx: c) Calculate the interferencearrow_forward
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- Black body (b) and purple eye (pr) are recessive autosomal mutations in Drosophila. Bridges are crossed b/b females with pr/pr males and in the F2 observed 684 wild type, 371 black-bodied, and 300 purple-eyed flies. Do these results indicate that the b and pr genes are closely linked? Explain. (Remember that there is no crossing-over in male Drosophila)..arrow_forwardThe wild-type (normal) fruit fly, Drosophila melanogaster, has straight wings and long bristles. Mutant strains have been isolated with either curled wings or short bristles. The genes representing these two mutant traits are located on separate chromosomes. Carefully examine the data from the five crosses below. (a) For each mutation, determine whether it is dominant or recessive. In each case, identify which crosses support your answer; and (b) define gene symbols and determine the genotypes of the parents for each cross. Cross 1. straight, short X straight, short 2. straight, long X straight, long 3. curled, long X straight, short 4. straight, short X straight, short 5. curled, short X straight, short straight wings, long bristles 30 120 40 40 20 Number of Progeny straight curled wings, wings, short long bristles bristles 90 10 0 40 120 60 40 40 0 20 curled wings, short bristles 30 0 40 0 60arrow_forwardThe wild-type (normal) fruit fly, Drosophila melanogaster, has straight wings and long bristles. Mutant strains have been isolated with either curled wings or short bristles. The genes representing these two mutant traits are located on separate chromosomes. Carefully examine the data from the five crosses below. (a) For each mutation, determine whether it is dominant or recessive. In each case, identify which crosses support your answer; and (b) define gene symbols and determine the genotypes of the parents for each cross.arrow_forward
- Male Drosophila from a true-breeding wild-type stock were irradiated with X-rays and then mated with females from a true-breeding stock carrying the following recessive mutations on the X chromosome: yellow body (y), crossveinless wings (cv), cut wings (ct), singed bristles (sn), and miniature wings (m). These markers are known to map in the order: Recessive alleles: y, cv, ct, sn, m Dominant alleles: y+, cv+, ct+, sn+, m+ y-cv-ct-sn-m у CV ct sn m X-rays х х X ct sn CV у m y+ CV+ ct+ sn+ m+ х X ? Exceptional female: Most of the female progeny of this cross were phenotypically wild type, but one female exhibited ct and sn mutant characteristics. When this exceptional ct sn female was mated with a male from the true-breeding wild-type stock, twice as many females as males appeared among the progeny. a. What is the nature of the X-ray-induced mutation present in the exceptional female? b. Draw the X chromosomes present in the exceptional ct sn female as they would appear during pairing…arrow_forwardTwo Drosophila flies that had normal (transparent, long) wings were mated. In the progeny, two new phenotypes appeared, dusky wings (having a semi-opaque appearance) and clipped wings (with squared ends). The progeny were as follows: Females: 179 transparent, long 58 transparent, clipped Males: 92 transparent, long 89 dusky, long 28 transparent, clipped 31 dusky, clipped a) Provide a genetic explanation for these results, showing genotypes of parents and of all progeny classes under your model. b) Design a test for your model.arrow_forwardCinnabar eyes (cn) and reduced bristles (rd) are linked autosomal recesive characters in Drosophila fruit flies. A homozygous wild-type female was crossed to a reduced, cinnabar male, and the F1 females were then crossed with cinnabar reduced males to obtain the F2. Of the 200 F2 offspring obtained, 86 were wild type, 13 were cinnabar, 17 were reduced and 84 were reduced and cinnabar.. What is the map distance between the cn and rd alleles? 8,4 mu 15 mu 17 mu 30 mu 13 muarrow_forward
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