Chapter 4, Problem 63E

Interpretation Introduction

Interpretation:

The reason should be explained for taking twice as much sodium hydroxide to react with all of the acid.

The reason should be explained for taking half as much sodium hydroxide to react with all of the hydrogen chloride acid.

Concept Introduction:

An acid which has ability to donate only one proton or hydrogen ion in an aqueous solution is known as monoprotic acid such as hydrogen chloride ( $\text{HCl}$ ). An acid which has ability to donate two protons or two hydrogen ions in the solution is known as diprotic acid such as sulfuric acid ( ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ ).

A base which has ability to donate only one hydroxide ion in an aqueous solution is known as monobasic base such as sodium hydroxide ( $\text{NaOH}$ ). A base which has ability to donate two hydroxide ions in the solution is known as dibasic base such as calcium hydroxide ( ${\text{Ba(OH)}}_2$ ).