Chemical Principles
8th Edition
ISBN: 9781305581982
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Chapter 4, Problem 109AE
A solution is prepared by dissolving 0.6706 g oxalic acid
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Chapter 4 Solutions
Chemical Principles
Ch. 4 - Prob. 1DQCh. 4 - Prob. 2DQCh. 4 - Prob. 3DQCh. 4 - Prob. 4DQCh. 4 - Prob. 5DQCh. 4 - The exposed electrodes of a light bulb are placed...Ch. 4 - Prob. 7DQCh. 4 - Prob. 8DQCh. 4 - Consider separate aqueous solutions of HCland...Ch. 4 - Prob. 10DQ
Ch. 4 - Prob. 11DQCh. 4 - Characterize strong electrolytes versus weak...Ch. 4 - The figures below are molecular-level...Ch. 4 - Prob. 14ECh. 4 - Differentiate between what happens when the...Ch. 4 - Commercial cold packs and hot packs are available...Ch. 4 - Prob. 17ECh. 4 - Prob. 18ECh. 4 - Prob. 19ECh. 4 - Prob. 20ECh. 4 - Prob. 21ECh. 4 - Prob. 22ECh. 4 - Prob. 23ECh. 4 - Prob. 24ECh. 4 - Prob. 25ECh. 4 - Prob. 26ECh. 4 - Prob. 27ECh. 4 - Prob. 28ECh. 4 - Prob. 29ECh. 4 - A stock solution containing Mn2+ ions is prepared...Ch. 4 - Prob. 31ECh. 4 - Prob. 32ECh. 4 - List the formulas of three soluble bromide salts...Ch. 4 - Prob. 34ECh. 4 - Prob. 35ECh. 4 - Prob. 36ECh. 4 - Prob. 37ECh. 4 - Prob. 38ECh. 4 - Write the balanced molecular, complete, and net...Ch. 4 - How would you separate the following ions in...Ch. 4 - Prob. 41ECh. 4 - Prob. 42ECh. 4 - Prob. 43ECh. 4 - What volume of 0.100 M Na3PO4 is required to...Ch. 4 - Prob. 45ECh. 4 - Prob. 46ECh. 4 - Prob. 47ECh. 4 - The following drawings represent aqueous...Ch. 4 - Prob. 49ECh. 4 - Prob. 50ECh. 4 - Prob. 51ECh. 4 - Prob. 52ECh. 4 - Saccharin (C7H5NO3S) is sometimes dispensed in...Ch. 4 - Prob. 54ECh. 4 - A 1.42-g sample of a pure compound with formula...Ch. 4 - Prob. 56ECh. 4 - Prob. 57ECh. 4 - Prob. 58ECh. 4 - Prob. 59ECh. 4 - Prob. 60ECh. 4 - Prob. 61ECh. 4 - Prob. 62ECh. 4 - Prob. 63ECh. 4 - Sodium hydroxide solution is usually standardized...Ch. 4 - Prob. 65ECh. 4 - Prob. 66ECh. 4 - Prob. 67ECh. 4 - A student titrates an unknown amount of...Ch. 4 - Prob. 69ECh. 4 - Prob. 70ECh. 4 - Hydrochloric acid (75.0 mL of 0.250 M) is added...Ch. 4 - Prob. 72ECh. 4 - Prob. 73ECh. 4 - Prob. 74ECh. 4 - Prob. 75ECh. 4 - Prob. 76ECh. 4 - Prob. 77ECh. 4 - Prob. 78ECh. 4 - Prob. 79ECh. 4 - Balance each of the following oxidationreduction...Ch. 4 - Prob. 81ECh. 4 - Prob. 82ECh. 4 - Prob. 83ECh. 4 - Prob. 84ECh. 4 - Prob. 85ECh. 4 - Prob. 86ECh. 4 - Prob. 87ECh. 4 - Prob. 88ECh. 4 - Prob. 89ECh. 4 - Prob. 90ECh. 4 - Prob. 91AECh. 4 - Prob. 92AECh. 4 - Consider a 1.50-g mixture of magnesium nitrate...Ch. 4 - Suppose 50.0 mL of 0.250 M CoCl2 solution is added...Ch. 4 - Prob. 95AECh. 4 - A mixture contains only NaCland Fe(NO3)3 . A...Ch. 4 - A mixture contains only sodium chloride and...Ch. 4 - Prob. 98AECh. 4 - A student added 50.0 mL of an NaOH solution...Ch. 4 - In a 1-L beaker, 203 mL of 0.307 M ammonium...Ch. 4 - It took 25.060.05 mL of a sodium hydroxide...Ch. 4 - You wish to prepare 1 L of a 0.02 M potassium...Ch. 4 - Citric acid, which can be obtained from lemon...Ch. 4 - Acetylsalicylic acid is the active ingredient in...Ch. 4 - A 6.50-g sample of a diprotic acid requires 137.5...Ch. 4 - Prob. 106AECh. 4 - Chlorisondamine chloride (C14H20Cl6N2) is a drug...Ch. 4 - Calculate the concentration of all ions present...Ch. 4 - A solution is prepared by dissolving 0.6706 g...Ch. 4 - For the following chemical reactions, determine...Ch. 4 - What volume of 0.100 M NaOH is required to...Ch. 4 - Prob. 112AECh. 4 - A 450.0-mL sample of a 0.257-M solution of silver...Ch. 4 - Prob. 114AECh. 4 - A 50.00-mL sample of aqueous Ca(OH)2 requires34.66...Ch. 4 - When organic compounds containing sulfur are...Ch. 4 - Assign the oxidation state for the element listed...Ch. 4 - The blood alcohol (C2H5OH) level can be determined...Ch. 4 - Zinc and magnesium metal each react with...Ch. 4 - A 10.00-g sample consisting of a mixture of...Ch. 4 - Consider the reaction of 19.0 g of zinc with...Ch. 4 - Consider an experiment in which two burets, Y and...Ch. 4 - A sample is a mixture of KCl and KBr. When 0.1024...Ch. 4 - You made 100.0 mL of a lead(II) nitrate solution...Ch. 4 - Polychlorinated biphenyls (PCBs) have been used...Ch. 4 - Prob. 126CPCh. 4 - Prob. 127CPCh. 4 - Chromium has been investigated as a coating for...Ch. 4 - Prob. 129CPCh. 4 - Three students were asked to find the identity of...Ch. 4 - A sample is a mixture of AgNO3,CuCl2,andFeCl3...Ch. 4 - Prob. 132MPCh. 4 - You have two 500.0-mL aqueous solutions. Solution...
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- When 10. L of water is added to 3.0 L of 6.0 M H2SO4, what is the molarity of the resulting solution? Assume the volumes are additive.arrow_forward39. Standard solutions of calcium ion used to test for water hardness are prepared by dissolving pure calcium carbonate. CaCO3, in dilute hydrochloric acid. A 1.745-g sample of CaCO3 is placed in a 250.O-mL volumetric flask and dissolved in HCI. Then the solution is diluted to the calibration mark of the volumetric flask. Calculate the resulting molarity of calcium ion.arrow_forwardTwenty-five mL of a 0.388 M solution of Na2SO4 is mixed with 35.3 mL of 0.229 M Na2SO4. What is the molarity of the resulting solution? Assume that the volumes are additive.arrow_forward
- 3.106 Twenty-five mL of a 0.388 M solution of Na2SO4 is mixed with 35.3 mL of 0.229 M Na2SO4. What is the molarity of the resulting solution? Assume that the volumes are additive.arrow_forwardonsider separate aqueous solutions of HCI and H2S04 with the same concentrations in terms of molarity. You wish to neutralize au aqueous solution of’ NaOH. For which acid solution would you need to add more volume (in mL) to neutralize the base? The HCI solution. The H2SO4 solution. You need to know the acid concentrations to answer this question. You need to know the volume and concentration of’ the NaOH solution to answer this question. c and d plain your answer.arrow_forwardCitric acid, which can be obtained from lemon juice, has the molecular formula C6H8O7. A 0.250-g sample of citric acid dissolved in 25.0 mL of water requires 37.2 mL of 0.105 M NaOH for complete neutralization. What number of acidic hydrogens per molecule does citric acid have?arrow_forward
- What is the molarity of a solution of sodium hydrogen sulfate that is prepared by dissolving 9.21 g NaHSO4 in enough water to form 2.00-L solution? What is the molarity of each ion in the solution?arrow_forwardLactic acid, C3H6O3 is the acid present in sour milk. A 0.100-g sample of pure lactic acid requires 12.95 mL of 0.0857 M sodium hydroxide for complete reaction. How many moles of hydroxide ion are required to neutralize one mole of lactic acid?arrow_forwardssume a highly magnified view of a solution of HCI that allows you to “see” the HCl. Draw this magnified view. If you dropped in a piece of magnesium, the magnesium would disappear, and hydrogen gas would he released. Represent this change using symbols for the elements, and write the balanced equation.arrow_forward
- A student weighs out a 4.80-g sample of aluminum bromide, transfers it to a 100-mL volumetric flask, adds enough water to dissolve it, and then adds water to the 100-mL mark. What is the molarity of aluminum bromide in the resulting solution?arrow_forwardYou are given a solid mixture of NaNO2 and NaCl and are asked to analyze it for the amount of NaNO2 present. To do so, you allow the mixture to react with sulfamic acid, HSO3NH2, in water according to the equation NaNO2(aq) + HSO3NH2(aq) NaHSO4(aq) + H2O() + N2(g) What is the weight percentage of NaNO2 in 1.232 g of the solid mixture if reaction with sulfa-mic acid produces 295 mL of dry N2 gas with a pressure of 713 mm Hg at 21.0 C?arrow_forwardA solution of potassium permanganate reacts with oxalic acid, H2C2O4, to form carbon dioxide and solid manganese(IV) oxide (MnO2) according to the equation 3H2C2O4(aq)+2MnO4(aq)+2 H+(aq)6CO2(g)+2MnO2(s)+4H2O (a) If 20.0 mL of 0.300 M potassium permanganate are required to react with 13.7 mL of oxalic acid, what is the molarity of the oxalic acid? (b) What is the mass of manganese(IV) oxide formed?arrow_forward
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY