The molar concentration of final solution, if it is prepared from taking 100.0 μL of the stock solution which is further diluted to a volume of 100 ml is to be calculated. Concept introduction: The molarity of any substance in a solution is equivalent to concentration. It is obtained from the moles of solute present in per unit volume of the solution. The formula to calculate the molarity in a solution is as follows. Molarity = Moles of solute Volume of solution ( L )

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2. A typical cup of tea (150.0 mL) is prepared. One teaspoon of glucose (C6H12O6; m.w. = 180.156 g mol-¹) is added (approximately 4.0 g of sugar). The resulting volume of solution is 152.6 mL, your standard cup of tea. Treating the sugar as the solute and the tea as water, the solvent. Calculate the following concentrations: a) M b) m c) % by mass d) mol fraction

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Chapter 4, Problem 29E

Interpretation Introduction

Interpretation: The molar concentration of final solution, if it is prepared from taking 100.0 μL of the stock solution which is further diluted to a volume of 100 ml is to be calculated.

Concept introduction: The molarity of any substance in a solution is equivalent to concentration. It is obtained from the moles of solute present in per unit volume of the solution.

The formula to calculate the molarity in a solution is as follows.

Molarity=Moles of solute Volume of solution(L)

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