Concept explainers
a.
To find:Monthly cost.
a.
Answer to Problem 74PFA
Monthly fee = $40.
Explanation of Solution
Given information:
Total fee after three months = $295
Total fee after eight months = $495
We know from given information
Total fee = Initial membership fee + Fee for
Let initial membership fee be
Let Monthly fee for one month be K.
Therefore
Total fee for
Given
Total fee for three months = $295
Total fee for eight months = $495
Subtracting equation-(2) with equation-(1)
We get
Therefore
Monthly fee =
b.
To find: Initial membership fee.
b.
Answer to Problem 74PFA
Initial membership fee = $175
Explanation of Solution
Given information:
Total fee after three months = $295
Total fee after eight months = $495
We know from given information
Total fee = Initial membership fee + Fee for
Let initial membership fee be
Let Monthly fee for one month be K.
Therefore
Total fee for
Given
Total fee for three months = $295
Total fee for eight months = $495
Subtracting equation-(2) with equation-(1)
We get
Therefore
Monthly fee =
Substituting value of K in equation-(1)
We get
Therefore
Initial membership fee =
c.
To find:Equation for the total cost C as a function of the number of months,
c.
Answer to Problem 74PFA
Equation of given situation is
Explanation of Solution
Given information:
Total fee after three months = $295
Total fee after eight months = $495
We know from given information
Total fee = Initial membership fee + Fee for
Let initial membership fee be
Let Monthly fee for one month be K.
Therefore
Total fee for
Given
Total fee for three months = $295
Total fee for eight months = $495
Subtracting equation-(2) with equation-(1)
We get
Therefore
Monthly fee =
Substituting value of K in equation-(1)
We get
Therefore
Initial membership fee =
Substituting values of K and
We get
Therefore
Equation of given situation is
d.
To find: Earnings of Paul after one year.
d.
Answer to Problem 74PFA
Paul have to pay $655 after one year.
Explanation of Solution
Given information:
Total fee after three months = $295
Total fee after eight months = $495
represents the equation of given situation
We need to find cost for 1 -year.
1 year = 12 months
Therefore
Substitute
We get
Therefore
Paul have to pay $655 after one year.
Chapter 3 Solutions
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Additional Math Textbook Solutions
Algebra and Trigonometry
College Algebra in Context with Applications for the Managerial, Life, and Social Sciences (5th Edition)
Linear Algebra with Applications (2-Download)
Graphical Approach To College Algebra
Algebra and Trigonometry (6th Edition)
- Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSONContemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage LearningLinear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
- Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSONIntroduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge PressCollege Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education