Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN: 9780079039897
Author: Carter
Publisher: McGraw Hill
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Question
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Chapter 3.1, Problem 35PPS

a.

To determine

To make table values for the points (v,p)

a.

Expert Solution
Check Mark

Explanation of Solution

Given:

The given equation is: p=0.15v

Where, v denotes the total number of potential viewers in millions

  p denotes the total number of viewers in millions.

Example for the development of table:

Let the number of potential viewers be 4 millions, which means v=4

Now, p=0.15×4=0.6 , which means for 4 million of potential viewers there are 0.6 millions of viewers who watch the show.

Similarly, different values of v will give different values of p which will help to make a table for the given relation

Table:

    Values of v (in millions)Values of p (in millions)
    0 0
    1 0.15
    1.5 0.225
    2 0.3
    2.3 0.345
    3 0.45

Conclusion:

From the table it can be interpreted that, with the increase in number of potential viewers there is also rise in the number of viewers.

b.

To determine

To graph the given equation

b.

Expert Solution
Check Mark

Explanation of Solution

Given:

  p=0.15v

Calculation for graph:

Consider p=0.15v

    Values of v (in millions)Values of p (in millions)
    0 0
    1 0.15
    1.5 0.225
    2 0.3
    2.3 0.345
    3 0.45

By taking different values of v , the graph can be plotted.

Given:

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018, Chapter 3.1, Problem 35PPS , additional homework tip  1

Interpretation:

The graph clearly shows a linear relation between v and p.

c.

To determine

To use the graph and estimate the number of viewers who watched the show when the number of potential viewers were 14 million.

c.

Expert Solution
Check Mark

Answer to Problem 35PPS

The number of viewers who watched the show will be 2.1 million.

Explanation of Solution

Graph:

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018, Chapter 3.1, Problem 35PPS , additional homework tip  2

Conclusion:

From the graph it is clear that when there were 14 million potential viewers, 2.1 million viewers watched the show.

d.

To determine

To explain why the value of v cannot be considered negative

d.

Expert Solution
Check Mark

Explanation of Solution

The given expression p=0.15v , shows the relation between the number of potential viewers and the number of viewers who watched the show.

So, mathematically v represents the count of people which cannot be negative, this is the reason why the values of v cannot be taken as negative values.

Conclusion:

Hence, after the analysis it is clear that it would be meaningless to consider the negative values of v.

Chapter 3 Solutions

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

Ch. 3.1 - Prob. 2CYUCh. 3.1 - Prob. 3CYUCh. 3.1 - Prob. 4CYUCh. 3.1 - Prob. 5CYUCh. 3.1 - Prob. 6CYUCh. 3.1 - Prob. 7CYUCh. 3.1 - Prob. 8CYUCh. 3.1 - Prob. 9CYUCh. 3.1 - Prob. 10CYUCh. 3.1 - Prob. 11CYUCh. 3.1 - Prob. 12CYUCh. 3.1 - Prob. 13PPSCh. 3.1 - Prob. 14PPSCh. 3.1 - Prob. 15PPSCh. 3.1 - Prob. 16PPSCh. 3.1 - Prob. 17PPSCh. 3.1 - Prob. 18PPSCh. 3.1 - Prob. 19PPSCh. 3.1 - Prob. 20PPSCh. 3.1 - Prob. 21PPSCh. 3.1 - Prob. 22PPSCh. 3.1 - Prob. 23PPSCh. 3.1 - Prob. 24PPSCh. 3.1 - Prob. 25PPSCh. 3.1 - Prob. 26PPSCh. 3.1 - Prob. 27PPSCh. 3.1 - Prob. 28PPSCh. 3.1 - Prob. 29PPSCh. 3.1 - Prob. 30PPSCh. 3.1 - Prob. 31PPSCh. 3.1 - Prob. 32PPSCh. 3.1 - Prob. 33PPSCh. 3.1 - Prob. 34PPSCh. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 36PPSCh. 3.1 - Prob. 37PPSCh. 3.1 - Prob. 38PPSCh. 3.1 - Prob. 39PPSCh. 3.1 - Prob. 40PPSCh. 3.1 - Prob. 41PPSCh. 3.1 - Prob. 42PPSCh. 3.1 - Prob. 43PPSCh. 3.1 - Prob. 44PPSCh. 3.1 - Prob. 45PPSCh. 3.1 - Prob. 46PPSCh. 3.1 - Prob. 47PPSCh. 3.1 - Prob. 48PPSCh. 3.1 - Prob. 49PPSCh. 3.1 - 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Prob. 3CYUCh. 3.5 - Prob. 4CYUCh. 3.5 - Prob. 5CYUCh. 3.5 - Prob. 6CYUCh. 3.5 - Prob. 7CYUCh. 3.5 - Prob. 8CYUCh. 3.5 - Prob. 9CYUCh. 3.5 - Prob. 10CYUCh. 3.5 - Prob. 11CYUCh. 3.5 - Prob. 12PPSCh. 3.5 - Prob. 13PPSCh. 3.5 - Prob. 14PPSCh. 3.5 - Prob. 15PPSCh. 3.5 - Prob. 16PPSCh. 3.5 - Prob. 17PPSCh. 3.5 - Prob. 18PPSCh. 3.5 - Prob. 19PPSCh. 3.5 - Prob. 20PPSCh. 3.5 - Prob. 21PPSCh. 3.5 - Prob. 22PPSCh. 3.5 - Prob. 23PPSCh. 3.5 - Prob. 24PPSCh. 3.5 - Prob. 25PPSCh. 3.5 - Prob. 26PPSCh. 3.5 - Prob. 27PPSCh. 3.5 - Prob. 28PPSCh. 3.5 - Prob. 29PPSCh. 3.5 - Prob. 30PPSCh. 3.5 - Prob. 31PPSCh. 3.5 - Prob. 32PPSCh. 3.5 - Prob. 33PPSCh. 3.5 - Prob. 34PPSCh. 3.5 - Prob. 35PPSCh. 3.5 - Prob. 36PPSCh. 3.5 - Prob. 37PPSCh. 3.5 - Prob. 38PPSCh. 3.5 - Prob. 39PPSCh. 3.5 - Prob. 40PPSCh. 3.5 - Prob. 41PPSCh. 3.5 - Prob. 42PPSCh. 3.5 - Prob. 43PPSCh. 3.5 - Prob. 44PPSCh. 3.5 - Prob. 45PPSCh. 3.5 - Prob. 46PPSCh. 3.5 - Prob. 47PPSCh. 3.5 - Prob. 48PPSCh. 3.5 - Prob. 49PPSCh. 3.5 - Prob. 50PPSCh. 3.5 - Prob. 51PPSCh. 3.5 - Prob. 52HPCh. 3.5 - Prob. 53HPCh. 3.5 - Prob. 54HPCh. 3.5 - Prob. 55HPCh. 3.5 - Prob. 56HPCh. 3.5 - Prob. 57PFACh. 3.5 - Prob. 58PFACh. 3.5 - Prob. 59PFACh. 3.5 - Prob. 60PFACh. 3.5 - Prob. 61PFACh. 3.5 - Prob. 62PFACh. 3.5 - Prob. 63PFACh. 3.5 - Prob. 64PFACh. 3.6 - Prob. 1AGPCh. 3.6 - Prob. 1BGPCh. 3.6 - Prob. 2GPCh. 3.6 - Prob. 3AGPCh. 3.6 - Prob. 3BGPCh. 3.6 - Prob. 3CGPCh. 3.6 - Prob. 3DGPCh. 3.6 - Prob. 4AGPCh. 3.6 - Prob. 4BGPCh. 3.6 - Prob. 1CYUCh. 3.6 - Prob. 2CYUCh. 3.6 - Prob. 3CYUCh. 3.6 - Prob. 4CYUCh. 3.6 - Prob. 5CYUCh. 3.6 - Prob. 6CYUCh. 3.6 - Prob. 7CYUCh. 3.6 - Prob. 8PPSCh. 3.6 - Prob. 9PPSCh. 3.6 - Prob. 10PPSCh. 3.6 - Prob. 11PPSCh. 3.6 - Prob. 12PPSCh. 3.6 - Prob. 13PPSCh. 3.6 - Prob. 14PPSCh. 3.6 - Prob. 15PPSCh. 3.6 - Prob. 16PPSCh. 3.6 - Prob. 17PPSCh. 3.6 - Prob. 18PPSCh. 3.6 - Prob. 19PPSCh. 3.6 - Prob. 20PPSCh. 3.6 - Prob. 21PPSCh. 3.6 - Prob. 22PPSCh. 3.6 - Prob. 23PPSCh. 3.6 - Prob. 24PPSCh. 3.6 - Prob. 25PPSCh. 3.6 - Prob. 26PPSCh. 3.6 - Prob. 27PPSCh. 3.6 - Prob. 28PPSCh. 3.6 - Prob. 29PPSCh. 3.6 - Prob. 30PPSCh. 3.6 - Prob. 31PPSCh. 3.6 - Prob. 32HPCh. 3.6 - Prob. 33HPCh. 3.6 - Prob. 34HPCh. 3.6 - Prob. 35HPCh. 3.6 - Prob. 36HPCh. 3.6 - Prob. 37PFACh. 3.6 - Prob. 38PFACh. 3.6 - Prob. 39PFACh. 3.6 - Prob. 40PFACh. 3.6 - Prob. 41PFACh. 3.6 - Prob. 42PFACh. 3.6 - Prob. 43PFACh. 3.7 - Prob. 1GPCh. 3.7 - Prob. 2GPCh. 3.7 - Prob. 3GPCh. 3.7 - Prob. 4GPCh. 3.7 - Prob. 1CYUCh. 3.7 - Prob. 2CYUCh. 3.7 - Prob. 3CYUCh. 3.7 - Prob. 4CYUCh. 3.7 - Prob. 5CYUCh. 3.7 - Prob. 6CYUCh. 3.7 - Prob. 7CYUCh. 3.7 - Prob. 8PPSCh. 3.7 - Prob. 9PPSCh. 3.7 - Prob. 10PPSCh. 3.7 - Prob. 11PPSCh. 3.7 - Prob. 12PPSCh. 3.7 - Prob. 13PPSCh. 3.7 - Prob. 14PPSCh. 3.7 - Prob. 15PPSCh. 3.7 - Prob. 16PPSCh. 3.7 - Prob. 17PPSCh. 3.7 - Prob. 18PPSCh. 3.7 - Prob. 19PPSCh. 3.7 - Prob. 20PPSCh. 3.7 - Prob. 21PPSCh. 3.7 - Prob. 22PPSCh. 3.7 - Prob. 23PPSCh. 3.7 - Prob. 24PPSCh. 3.7 - Prob. 25PPSCh. 3.7 - Prob. 26PPSCh. 3.7 - Prob. 27PPSCh. 3.7 - Prob. 28PPSCh. 3.7 - 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Prob. 17PTCh. 3 - Prob. 18PTCh. 3 - Prob. 19PTCh. 3 - Prob. 20PTCh. 3 - Prob. 21PTCh. 3 - Prob. 22PTCh. 3 - Prob. 23PTCh. 3 - Prob. 24PTCh. 3 - Prob. 25PTCh. 3 - Prob. 26PTCh. 3 - Prob. 27PTCh. 3 - Prob. 1PFACh. 3 - Prob. 2PFACh. 3 - Prob. 3PFACh. 3 - Prob. 4PFACh. 3 - Prob. 5PFACh. 3 - Prob. 6PFACh. 3 - Prob. 7PFACh. 3 - Prob. 8PFACh. 3 - Prob. 9PFACh. 3 - Prob. 10PFACh. 3 - Prob. 11PFACh. 3 - Prob. 12PFACh. 3 - Prob. 13PFACh. 3 - Prob. 14PFA

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Algebra
ISBN:9780980232776
Author:Gilbert Strang
Publisher:Wellesley-Cambridge Press
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College Algebra (Collegiate Math)
Algebra
ISBN:9780077836344
Author:Julie Miller, Donna Gerken
Publisher:McGraw-Hill Education
What is Ellipse?; Author: Don't Memorise;https://www.youtube.com/watch?v=nzwCInIMlU4;License: Standard YouTube License, CC-BY