Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN: 9780079039897
Author: Carter
Publisher: McGraw Hill
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Chapter 3.2, Problem 36PPS
To determine

To find: Zero of the given equation w=0.3d0.5 and to write its mean in the context of given situation. Also to identify the domain and range.

Expert Solution & Answer
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Answer to Problem 36PPS

Zero of the equation is d=53 and its means that in 53 and it means that in 53 days or 1 day,16 hours, Parts of New Orleans will be above the sea.

Explanation of Solution

Given information: Parts of New Orleans lie 0.5 meter below sea level. After d days of rain the equation w=0.3d0.5

    represents the water level w in meters.

Concept used: Zero of an equation is obtained by plug in it equal to 0 and then solving it for independent variable d . And d represents number of days and w the water level in meters.

Calculation: To plug in w=0 in it and on solving it for d ,

  0=0.3d0.50.3d=0.5d=53=113

So, its only zero of this equation is, d=53 .  

Conclusion: Value d=53 means that in 53=123 days or in 1 day 16 hours, the parts of New Orleans will be at the surface of sea level.

Chapter 3 Solutions

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

Ch. 3.1 - Prob. 2CYUCh. 3.1 - Prob. 3CYUCh. 3.1 - Prob. 4CYUCh. 3.1 - Prob. 5CYUCh. 3.1 - Prob. 6CYUCh. 3.1 - Prob. 7CYUCh. 3.1 - Prob. 8CYUCh. 3.1 - Prob. 9CYUCh. 3.1 - Prob. 10CYUCh. 3.1 - Prob. 11CYUCh. 3.1 - Prob. 12CYUCh. 3.1 - Prob. 13PPSCh. 3.1 - Prob. 14PPSCh. 3.1 - Prob. 15PPSCh. 3.1 - Prob. 16PPSCh. 3.1 - Prob. 17PPSCh. 3.1 - Prob. 18PPSCh. 3.1 - Prob. 19PPSCh. 3.1 - Prob. 20PPSCh. 3.1 - Prob. 21PPSCh. 3.1 - Prob. 22PPSCh. 3.1 - Prob. 23PPSCh. 3.1 - Prob. 24PPSCh. 3.1 - Prob. 25PPSCh. 3.1 - Prob. 26PPSCh. 3.1 - Prob. 27PPSCh. 3.1 - Prob. 28PPSCh. 3.1 - Prob. 29PPSCh. 3.1 - Prob. 30PPSCh. 3.1 - Prob. 31PPSCh. 3.1 - Prob. 32PPSCh. 3.1 - Prob. 33PPSCh. 3.1 - Prob. 34PPSCh. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 36PPSCh. 3.1 - Prob. 37PPSCh. 3.1 - Prob. 38PPSCh. 3.1 - Prob. 39PPSCh. 3.1 - Prob. 40PPSCh. 3.1 - Prob. 41PPSCh. 3.1 - Prob. 42PPSCh. 3.1 - Prob. 43PPSCh. 3.1 - Prob. 44PPSCh. 3.1 - Prob. 45PPSCh. 3.1 - Prob. 46PPSCh. 3.1 - Prob. 47PPSCh. 3.1 - Prob. 48PPSCh. 3.1 - Prob. 49PPSCh. 3.1 - 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Prob. 17PTCh. 3 - Prob. 18PTCh. 3 - Prob. 19PTCh. 3 - Prob. 20PTCh. 3 - Prob. 21PTCh. 3 - Prob. 22PTCh. 3 - Prob. 23PTCh. 3 - Prob. 24PTCh. 3 - Prob. 25PTCh. 3 - Prob. 26PTCh. 3 - Prob. 27PTCh. 3 - Prob. 1PFACh. 3 - Prob. 2PFACh. 3 - Prob. 3PFACh. 3 - Prob. 4PFACh. 3 - Prob. 5PFACh. 3 - Prob. 6PFACh. 3 - Prob. 7PFACh. 3 - Prob. 8PFACh. 3 - Prob. 9PFACh. 3 - Prob. 10PFACh. 3 - Prob. 11PFACh. 3 - Prob. 12PFACh. 3 - Prob. 13PFACh. 3 - Prob. 14PFA

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