Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN: 9780079039897
Author: Carter
Publisher: McGraw Hill
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Question
Chapter 3.4, Problem 60PPS
a.
To determine
To describe: The characteristic of a graph that represents the circulation after 2013.
a.
Expert Solution
Explanation of Solution
Given:
The rate of change of circulation of the magazine is declining steadily for last 10 years. The circulation was about 450,000 subscribers in 2013.
The graph for the given scenario can be represented using the x-axis to represent the number of years since 2013 and y-axis the number of subscribers.
Since the number of subscribers is declining steadily, the graph will be a straight line with a negative slope with y-intercept as 450,000.
b.
To determine
To describe: The assumption made about the graph of the circulation of the magazine.
b.
Expert Solution
Answer to Problem 60PPS
The circulation continues to decline at the same rate after 2013.
Explanation of Solution
Given:
The rate of change of circulation of the magazine is declining steadily for last 10 years. The circulation was about 450,000 subscribers in 2013.
Since the number of subscribers is declining steadily, so it can be assumed that the number of subscribers continues to decline at the same rate after 2013.
c.
To determine
To predict: The future of the magazine.
c.
Expert Solution
Answer to Problem 60PPS
The circulation continues to decline at the same rate after 2013.
Explanation of Solution
Given:
The rate of change of circulation of the magazine is declining steadily for last 10 years. The circulation was about 450,000 subscribers in 2013.
Since the number of subscribers is declining steadily, so it can be assumed that the number of subscribers continues to decline at the same rate after 2013. Now, draw the graph for the circulation of the magazine as shown below.
The graph shows that the number of subscribers will become zero in long run.
Chapter 3 Solutions
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Ch. 3.1 - Prob. 1AGPCh. 3.1 - Prob. 1BGPCh. 3.1 - Prob. 2GPCh. 3.1 - Prob. 3GPCh. 3.1 - Prob. 4AGPCh. 3.1 - Prob. 4BGPCh. 3.1 - Prob. 5AGPCh. 3.1 - Prob. 5BGPCh. 3.1 - Prob. 5CGPCh. 3.1 - Prob. 1CYU
Ch. 3.1 - Prob. 2CYUCh. 3.1 - Prob. 3CYUCh. 3.1 - Prob. 4CYUCh. 3.1 - Prob. 5CYUCh. 3.1 - Prob. 6CYUCh. 3.1 - Prob. 7CYUCh. 3.1 - Prob. 8CYUCh. 3.1 - Prob. 9CYUCh. 3.1 - Prob. 10CYUCh. 3.1 - Prob. 11CYUCh. 3.1 - Prob. 12CYUCh. 3.1 - Prob. 13PPSCh. 3.1 - Prob. 14PPSCh. 3.1 - Prob. 15PPSCh. 3.1 - Prob. 16PPSCh. 3.1 - Prob. 17PPSCh. 3.1 - Prob. 18PPSCh. 3.1 - Prob. 19PPSCh. 3.1 - Prob. 20PPSCh. 3.1 - Prob. 21PPSCh. 3.1 - Prob. 22PPSCh. 3.1 - Prob. 23PPSCh. 3.1 - Prob. 24PPSCh. 3.1 - Prob. 25PPSCh. 3.1 - Prob. 26PPSCh. 3.1 - Prob. 27PPSCh. 3.1 - Prob. 28PPSCh. 3.1 - Prob. 29PPSCh. 3.1 - Prob. 30PPSCh. 3.1 - Prob. 31PPSCh. 3.1 - Prob. 32PPSCh. 3.1 - Prob. 33PPSCh. 3.1 - Prob. 34PPSCh. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 36PPSCh. 3.1 - Prob. 37PPSCh. 3.1 - Prob. 38PPSCh. 3.1 - Prob. 39PPSCh. 3.1 - Prob. 40PPSCh. 3.1 - Prob. 41PPSCh. 3.1 - Prob. 42PPSCh. 3.1 - Prob. 43PPSCh. 3.1 - Prob. 44PPSCh. 3.1 - Prob. 45PPSCh. 3.1 - Prob. 46PPSCh. 3.1 - Prob. 47PPSCh. 3.1 - Prob. 48PPSCh. 3.1 - Prob. 49PPSCh. 3.1 - 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Prob. 55PPSCh. 3.3 - Prob. 56PPSCh. 3.3 - Prob. 57PPSCh. 3.3 - Prob. 58PPSCh. 3.4 - Prob. 1AGPCh. 3.4 - Prob. 1BGPCh. 3.4 - Prob. 2AGPCh. 3.4 - Prob. 2BGPCh. 3.4 - Prob. 3AGPCh. 3.4 - Prob. 3BGPCh. 3.4 - Prob. 4GPCh. 3.4 - Prob. 5GPCh. 3.4 - Prob. 1CYUCh. 3.4 - Prob. 2CYUCh. 3.4 - Prob. 3CYUCh. 3.4 - Prob. 4CYUCh. 3.4 - Prob. 5CYUCh. 3.4 - Prob. 6CYUCh. 3.4 - Prob. 7CYUCh. 3.4 - Prob. 8CYUCh. 3.4 - Prob. 9CYUCh. 3.4 - Prob. 10CYUCh. 3.4 - Prob. 11CYUCh. 3.4 - Prob. 12CYUCh. 3.4 - Prob. 13CYUCh. 3.4 - Prob. 14CYUCh. 3.4 - Prob. 15CYUCh. 3.4 - Prob. 16CYUCh. 3.4 - Prob. 17PPSCh. 3.4 - Prob. 18PPSCh. 3.4 - Prob. 19PPSCh. 3.4 - Prob. 20PPSCh. 3.4 - Prob. 21PPSCh. 3.4 - Prob. 22PPSCh. 3.4 - Prob. 23PPSCh. 3.4 - Prob. 24PPSCh. 3.4 - Prob. 25PPSCh. 3.4 - Prob. 26PPSCh. 3.4 - Prob. 27PPSCh. 3.4 - Prob. 28PPSCh. 3.4 - Prob. 29PPSCh. 3.4 - Prob. 30PPSCh. 3.4 - Prob. 31PPSCh. 3.4 - Prob. 32PPSCh. 3.4 - Prob. 33PPSCh. 3.4 - Prob. 34PPSCh. 3.4 - Prob. 35PPSCh. 3.4 - Prob. 36PPSCh. 3.4 - Prob. 37PPSCh. 3.4 - 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Prob. 3CYUCh. 3.5 - Prob. 4CYUCh. 3.5 - Prob. 5CYUCh. 3.5 - Prob. 6CYUCh. 3.5 - Prob. 7CYUCh. 3.5 - Prob. 8CYUCh. 3.5 - Prob. 9CYUCh. 3.5 - Prob. 10CYUCh. 3.5 - Prob. 11CYUCh. 3.5 - Prob. 12PPSCh. 3.5 - Prob. 13PPSCh. 3.5 - Prob. 14PPSCh. 3.5 - Prob. 15PPSCh. 3.5 - Prob. 16PPSCh. 3.5 - Prob. 17PPSCh. 3.5 - Prob. 18PPSCh. 3.5 - Prob. 19PPSCh. 3.5 - Prob. 20PPSCh. 3.5 - Prob. 21PPSCh. 3.5 - Prob. 22PPSCh. 3.5 - Prob. 23PPSCh. 3.5 - Prob. 24PPSCh. 3.5 - Prob. 25PPSCh. 3.5 - Prob. 26PPSCh. 3.5 - Prob. 27PPSCh. 3.5 - Prob. 28PPSCh. 3.5 - Prob. 29PPSCh. 3.5 - Prob. 30PPSCh. 3.5 - Prob. 31PPSCh. 3.5 - Prob. 32PPSCh. 3.5 - Prob. 33PPSCh. 3.5 - Prob. 34PPSCh. 3.5 - Prob. 35PPSCh. 3.5 - Prob. 36PPSCh. 3.5 - Prob. 37PPSCh. 3.5 - Prob. 38PPSCh. 3.5 - Prob. 39PPSCh. 3.5 - Prob. 40PPSCh. 3.5 - Prob. 41PPSCh. 3.5 - Prob. 42PPSCh. 3.5 - Prob. 43PPSCh. 3.5 - Prob. 44PPSCh. 3.5 - Prob. 45PPSCh. 3.5 - Prob. 46PPSCh. 3.5 - Prob. 47PPSCh. 3.5 - Prob. 48PPSCh. 3.5 - Prob. 49PPSCh. 3.5 - Prob. 50PPSCh. 3.5 - Prob. 51PPSCh. 3.5 - Prob. 52HPCh. 3.5 - Prob. 53HPCh. 3.5 - Prob. 54HPCh. 3.5 - Prob. 55HPCh. 3.5 - Prob. 56HPCh. 3.5 - Prob. 57PFACh. 3.5 - Prob. 58PFACh. 3.5 - Prob. 59PFACh. 3.5 - Prob. 60PFACh. 3.5 - Prob. 61PFACh. 3.5 - Prob. 62PFACh. 3.5 - Prob. 63PFACh. 3.5 - Prob. 64PFACh. 3.6 - Prob. 1AGPCh. 3.6 - Prob. 1BGPCh. 3.6 - Prob. 2GPCh. 3.6 - Prob. 3AGPCh. 3.6 - Prob. 3BGPCh. 3.6 - Prob. 3CGPCh. 3.6 - Prob. 3DGPCh. 3.6 - Prob. 4AGPCh. 3.6 - Prob. 4BGPCh. 3.6 - Prob. 1CYUCh. 3.6 - Prob. 2CYUCh. 3.6 - Prob. 3CYUCh. 3.6 - Prob. 4CYUCh. 3.6 - Prob. 5CYUCh. 3.6 - Prob. 6CYUCh. 3.6 - Prob. 7CYUCh. 3.6 - Prob. 8PPSCh. 3.6 - Prob. 9PPSCh. 3.6 - Prob. 10PPSCh. 3.6 - Prob. 11PPSCh. 3.6 - Prob. 12PPSCh. 3.6 - Prob. 13PPSCh. 3.6 - Prob. 14PPSCh. 3.6 - Prob. 15PPSCh. 3.6 - Prob. 16PPSCh. 3.6 - Prob. 17PPSCh. 3.6 - Prob. 18PPSCh. 3.6 - Prob. 19PPSCh. 3.6 - Prob. 20PPSCh. 3.6 - Prob. 21PPSCh. 3.6 - Prob. 22PPSCh. 3.6 - Prob. 23PPSCh. 3.6 - Prob. 24PPSCh. 3.6 - Prob. 25PPSCh. 3.6 - Prob. 26PPSCh. 3.6 - 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Prob. 13MCQCh. 3 - Prob. 14MCQCh. 3 - Prob. 15MCQCh. 3 - Prob. 16MCQCh. 3 - Prob. 17MCQCh. 3 - Prob. 18MCQCh. 3 - Prob. 19MCQCh. 3 - Prob. 20MCQCh. 3 - Prob. 21MCQCh. 3 - Prob. 22MCQCh. 3 - Prob. 23MCQCh. 3 - Prob. 24MCQCh. 3 - Prob. 25MCQCh. 3 - Prob. 26MCQCh. 3 - Prob. 1SGRCh. 3 - Prob. 2SGRCh. 3 - Prob. 3SGRCh. 3 - Prob. 4SGRCh. 3 - Prob. 5SGRCh. 3 - Prob. 6SGRCh. 3 - Prob. 7SGRCh. 3 - Prob. 8SGRCh. 3 - Prob. 9SGRCh. 3 - Prob. 10SGRCh. 3 - Prob. 11SGRCh. 3 - Prob. 12SGRCh. 3 - Prob. 13SGRCh. 3 - Prob. 14SGRCh. 3 - Prob. 15SGRCh. 3 - Prob. 16SGRCh. 3 - Prob. 17SGRCh. 3 - Prob. 18SGRCh. 3 - Prob. 19SGRCh. 3 - Prob. 20SGRCh. 3 - Prob. 21SGRCh. 3 - Prob. 22SGRCh. 3 - Prob. 23SGRCh. 3 - Prob. 24SGRCh. 3 - Prob. 25SGRCh. 3 - Prob. 26SGRCh. 3 - Prob. 27SGRCh. 3 - Prob. 28SGRCh. 3 - Prob. 29SGRCh. 3 - Prob. 30SGRCh. 3 - Prob. 31SGRCh. 3 - Prob. 32SGRCh. 3 - Prob. 33SGRCh. 3 - Prob. 34SGRCh. 3 - Prob. 35SGRCh. 3 - Prob. 36SGRCh. 3 - Prob. 37SGRCh. 3 - Prob. 38SGRCh. 3 - Prob. 39SGRCh. 3 - Prob. 40SGRCh. 3 - Prob. 41SGRCh. 3 - Prob. 42SGRCh. 3 - Prob. 43SGRCh. 3 - Prob. 44SGRCh. 3 - Prob. 45SGRCh. 3 - Prob. 46SGRCh. 3 - Prob. 47SGRCh. 3 - Prob. 48SGRCh. 3 - Prob. 49SGRCh. 3 - Prob. 50SGRCh. 3 - Prob. 51SGRCh. 3 - Prob. 52SGRCh. 3 - Prob. 53SGRCh. 3 - Prob. 54SGRCh. 3 - Prob. 55SGRCh. 3 - Prob. 56SGRCh. 3 - Prob. 57SGRCh. 3 - Prob. 58SGRCh. 3 - Prob. 59SGRCh. 3 - Prob. 60SGRCh. 3 - Prob. 61SGRCh. 3 - Prob. 62SGRCh. 3 - Prob. 63SGRCh. 3 - Prob. 64SGRCh. 3 - Prob. 65SGRCh. 3 - Prob. 66SGRCh. 3 - Prob. 67SGRCh. 3 - Prob. 68SGRCh. 3 - Prob. 69SGRCh. 3 - Prob. 70SGRCh. 3 - Prob. 71SGRCh. 3 - Prob. 72SGRCh. 3 - Prob. 73SGRCh. 3 - Prob. 74SGRCh. 3 - Prob. 75SGRCh. 3 - Prob. 76SGRCh. 3 - Prob. 77SGRCh. 3 - Prob. 78SGRCh. 3 - Prob. 1PTCh. 3 - Prob. 2PTCh. 3 - Prob. 3PTCh. 3 - Prob. 4PTCh. 3 - Prob. 5PTCh. 3 - Prob. 6PTCh. 3 - Prob. 7PTCh. 3 - Prob. 8PTCh. 3 - Prob. 9PTCh. 3 - Prob. 10PTCh. 3 - Prob. 11PTCh. 3 - Prob. 12PTCh. 3 - Prob. 13PTCh. 3 - Prob. 14PTCh. 3 - Prob. 15PTCh. 3 - Prob. 16PTCh. 3 - Prob. 17PTCh. 3 - Prob. 18PTCh. 3 - Prob. 19PTCh. 3 - Prob. 20PTCh. 3 - Prob. 21PTCh. 3 - Prob. 22PTCh. 3 - Prob. 23PTCh. 3 - Prob. 24PTCh. 3 - Prob. 25PTCh. 3 - Prob. 26PTCh. 3 - Prob. 27PTCh. 3 - Prob. 1PFACh. 3 - Prob. 2PFACh. 3 - Prob. 3PFACh. 3 - Prob. 4PFACh. 3 - Prob. 5PFACh. 3 - Prob. 6PFACh. 3 - Prob. 7PFACh. 3 - Prob. 8PFACh. 3 - Prob. 9PFACh. 3 - Prob. 10PFACh. 3 - Prob. 11PFACh. 3 - Prob. 12PFACh. 3 - Prob. 13PFACh. 3 - Prob. 14PFA
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- How much is the circumference of a circle whose diameter is 7 feet?C =π darrow_forwardHow to solve 2542/64.132arrow_forwardAssume that you fancy polynomial splines, while you actually need ƒ(t) = e²/3 – 1 for t€ [−1, 1]. See the figure for a plot of f(t). Your goal is to approximate f(t) with an inter- polating polynomial spline of degree d that is given as sa(t) = • Σk=0 Pd,k bd,k(t) so that sd(tk) = = Pd,k for tk = −1 + 2 (given d > 0) with basis functions bd,k(t) = Σi±0 Cd,k,i = • The special case of d 0 is trivial: the only basis function b0,0 (t) is constant 1 and so(t) is thus constant po,0 for all t = [−1, 1]. ...9 The d+1 basis functions bd,k (t) form a ba- sis Bd {ba,o(t), ba,1(t), bd,d(t)} of the function space of all possible sα (t) functions. Clearly, you wish to find out, which of them given a particular maximal degree d is the best-possible approximation of f(t) in the least- squares sense. _ 1 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 -0.1 -0.2 -0.3 -0.4 -0.5 -0.6 -0.7 -0.8 -0.9 -1 function f(t) = exp((2t)/3) - 1 to project -1 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0.1 0 0.1 0.2 0.3 0.4 0.5…arrow_forward
- An image processor considered a 750×750 pixels large subset of an image and converted it into gray-scale, resulting in matrix gIn - a false-color visualization of gIn is shown in the top-left below. He prepared a two-dim. box filter f1 as a 25×25 matrix with only the 5×5 values in the middle being non-zero – this filter is shown in the top-middle position below. He then convolved £1 with itself to get £2, before convolving £2 with itself to get f3. In both of the steps, he maintained the 25×25 size. Next, he convolved gIn with £3 to get gl. Which of the six panels below shows g1? Argue by explaining all the steps, so far: What did the image processor do when preparing ₤3? What image processing operation (from gin to g1) did he prepare and what's the effect that can be seen? Next, he convolved the rows of f3 with filter 1/2 (-1, 8, 0, -8, 1) to get f4 - you find a visualization of filter f 4 below. He then convolved gIn with f4 to get g2 and you can find the result shown below. What…arrow_forward3ur Colors are enchanting and elusive. A multitude of color systems has been proposed over a three-digits number of years - maybe more than the number of purposes that they serve... - Everyone knows the additive RGB color system – we usually serve light-emitting IT components like monitors with colors in that system. Here, we use c = (r, g, b) RGB with r, g, bЄ [0,1] to describe a color c. = T For printing, however, we usually use the subtractive CMY color system. The same color c becomes c = (c, m, y) CMY (1-c, 1-m, 1-y) RGB Note how we use subscripts to indicate with coordinate system the coordinates correspond to. Explain, why it is not possible to find a linear transformation between RGB and CMY coordinates. Farbenlehr c von Goethe Erster Band. Roſt einen Defte mit fergen up Tübingen, is et 3. Cotta'fden Babarblung. ISIO Homogeneous coordinates give us a work-around: If we specify colors in 4D, instead, with the 4th coordinate being the homogeneous coordinate h so that every actual…arrow_forwardCan someone provide an answer & detailed explanation please? Thank you kindly!arrow_forward
- Given the cubic function f(x) = x^3-6x^2 + 11x- 6, do the following: Plot the graph of the function. Find the critical points and determine whether each is a local minimum, local maximum, or a saddle point. Find the inflection point(s) (if any).Identify the intervals where the function is increasing and decreasing. Determine the end behavior of the graph.arrow_forwardGiven the quadratic function f(x) = x^2-4x+3, plot the graph of the function and find the following: The vertex of the parabola .The x-intercepts (if any). The y-intercept. Create graph also before solve.arrow_forwardwhat model best fits this dataarrow_forward
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