Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN: 9780079039897
Author: Carter
Publisher: McGraw Hill
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Question
Chapter 3, Problem 66SGR
To determine
To find: Cost to rent the gear for 30 minutes and check whether is it more for 40 minutes.
Expert Solution & Answer
Answer to Problem 66SGR
Cost of rent of gear for 30 minutes is $33.
And also cost of rent of gear for 30 minutes is $33.
Explanation of Solution
Given information:
Cost to rent the gear for 20 minutes intervals = $4
Insurance fee = $25
From given information,
For each 20 minutes interval rent is $4
Therefore,
The shopkeeper rents only for 20minutes intervals.
So, the cost of rent of gear for 40 minutes includes the cost of rent of gear for the time of
20 minutes to 40 minutes.
On cross-multiplication,
We get
The cost of rent for gear for 40 minutes is $8.
Since, the cost of rent of gear for 0 to 20 minutes is $4 and for 20 to 40 minutes is $8.
This pattern shows that, the cost of rent of gear is step function of time with intervals of 20 minutes and along with Insurance fee of $25.
The cost of rent of gear for 30 minutes is $8 and in addition with Insurance fee of $25.
Therefore, the cost of rent of gear for 30 minutes is $33.
As the cost is same for the time interval between 20 minutes and 40 minutes,
Therefore, the cost of rent of gear for 40 minutes is also $33.
Chapter 3 Solutions
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Ch. 3.1 - Prob. 1AGPCh. 3.1 - Prob. 1BGPCh. 3.1 - Prob. 2GPCh. 3.1 - Prob. 3GPCh. 3.1 - Prob. 4AGPCh. 3.1 - Prob. 4BGPCh. 3.1 - Prob. 5AGPCh. 3.1 - Prob. 5BGPCh. 3.1 - Prob. 5CGPCh. 3.1 - Prob. 1CYU
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Prob. 51PPSCh. 3.5 - Prob. 52HPCh. 3.5 - Prob. 53HPCh. 3.5 - Prob. 54HPCh. 3.5 - Prob. 55HPCh. 3.5 - Prob. 56HPCh. 3.5 - Prob. 57PFACh. 3.5 - Prob. 58PFACh. 3.5 - Prob. 59PFACh. 3.5 - Prob. 60PFACh. 3.5 - Prob. 61PFACh. 3.5 - Prob. 62PFACh. 3.5 - Prob. 63PFACh. 3.5 - Prob. 64PFACh. 3.6 - Prob. 1AGPCh. 3.6 - Prob. 1BGPCh. 3.6 - Prob. 2GPCh. 3.6 - Prob. 3AGPCh. 3.6 - Prob. 3BGPCh. 3.6 - Prob. 3CGPCh. 3.6 - Prob. 3DGPCh. 3.6 - Prob. 4AGPCh. 3.6 - Prob. 4BGPCh. 3.6 - Prob. 1CYUCh. 3.6 - Prob. 2CYUCh. 3.6 - Prob. 3CYUCh. 3.6 - Prob. 4CYUCh. 3.6 - Prob. 5CYUCh. 3.6 - Prob. 6CYUCh. 3.6 - Prob. 7CYUCh. 3.6 - Prob. 8PPSCh. 3.6 - Prob. 9PPSCh. 3.6 - Prob. 10PPSCh. 3.6 - Prob. 11PPSCh. 3.6 - Prob. 12PPSCh. 3.6 - Prob. 13PPSCh. 3.6 - Prob. 14PPSCh. 3.6 - Prob. 15PPSCh. 3.6 - Prob. 16PPSCh. 3.6 - Prob. 17PPSCh. 3.6 - Prob. 18PPSCh. 3.6 - Prob. 19PPSCh. 3.6 - Prob. 20PPSCh. 3.6 - Prob. 21PPSCh. 3.6 - Prob. 22PPSCh. 3.6 - Prob. 23PPSCh. 3.6 - Prob. 24PPSCh. 3.6 - Prob. 25PPSCh. 3.6 - Prob. 26PPSCh. 3.6 - 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- 14 14 4. The graph shows the printing rate of Printer A. Printer B can print at a rate of 25 pages per minute. How does the printing rate for Printer B compare to the printing rate for Printer A? The printing rate for Printer B is than the rate for Printer A because the rate of 25 pages per minute is than the rate of for Printer A. pages per minute RIJOUT 40 fy Printer Rat Number of Pages 8N WA 10 30 20 Printer A 0 0 246 Time (min) Xarrow_forwardOR 16 f(x) = Ef 16 χ по x²-2 410 | y = (x+2) + 4 Y-INT: y = 0 X-INT: X=0 VA: x=2 OA: y=x+2 0 X-INT: X=-2 X-INT: y = 2 VA 0 2 whole. 2-2 4 y - (x+2) = 27-270 + xxx> 2 क् above OA (x+2) OA x-2/x²+0x+0 2 x-2x 2x+O 2x-4 4 X<-1000 4/4/2<0 below Of y VA X=2 X-2 OA y=x+2 -2 2 (0,0) 2 χarrow_forwardI need help solving the equation 3x+5=8arrow_forward
- What is the domain, range, increasing intervals (theres 3), decreasing intervals, roots, y-intercepts, end behavior (approaches four times), leading coffiencent status (is it negative, positivie?) the degress status (zero, undifined etc ), the absolute max, is there a absolute minimum, relative minimum, relative maximum, the root is that has a multiplicity of 2, the multiplicity of 3.arrow_forwardWhat is the vertex, axis of symmerty, all of the solutions, all of the end behaviors, the increasing interval, the decreasing interval, describe all of the transformations that have occurred EXAMPLE Vertical shrink/compression (wider). or Vertical translation down, the domain and range of this graph EXAMPLE Domain: x ≤ -1 Range: y ≥ -4.arrow_forward4. Select all of the solutions for x²+x - 12 = 0? A. -12 B. -4 C. -3 D. 3 E 4 F 12 4 of 10arrow_forward
- 2. Select all of the polynomials with the degree of 7. A. h(x) = (4x + 2)³(x − 7)(3x + 1)4 B h(x) = (x + 7)³(2x + 1)^(6x − 5)² ☐ Ch(x)=(3x² + 9)(x + 4)(8x + 2)ª h(x) = (x + 6)²(9x + 2) (x − 3) h(x)=(-x-7)² (x + 8)²(7x + 4)³ Scroll down to see more 2 of 10arrow_forward1. If all of the zeros for a polynomial are included in the graph, which polynomial could the graph represent? 100 -6 -2 0 2 100 200arrow_forward3. Select the polynomial that matches the description given: Zero at 4 with multiplicity 3 Zero at −1 with multiplicity 2 Zero at -10 with multiplicity 1 Zero at 5 with multiplicity 5 ○ A. P(x) = (x − 4)³(x + 1)²(x + 10)(x — 5)³ B - P(x) = (x + 4)³(x − 1)²(x − 10)(x + 5)³ ○ ° P(x) = (1 − 3)'(x + 2)(x + 1)"'" (x — 5)³ 51 P(r) = (x-4)³(x − 1)(x + 10)(x − 5 3 of 10arrow_forward
- Match the equation, graph, and description of transformation. Horizontal translation 1 unit right; vertical translation 1 unit up; vertical shrink of 1/2; reflection across the x axis Horizontal translation 1 unit left; vertical translation 1 unit down; vertical stretch of 2 Horizontal translation 2 units right; reflection across the x-axis Vertical translation 1 unit up; vertical stretch of 2; reflection across the x-axis Reflection across the x - axis; vertical translation 2 units down Horizontal translation 2 units left Horizontal translation 2 units right Vertical translation 1 unit down; vertical shrink of 1/2; reflection across the x-axis Vertical translation 2 units down Horizontal translation 1 unit left; vertical translation 2 units up; vertical stretch of 2; reflection across the x - axis f(x) = - =-½ ½ (x − 1)²+1 f(x) = x²-2 f(x) = -2(x+1)²+2 f(x)=2(x+1)²-1 f(x)=-(x-2)² f(x)=(x-2)² f(x) = f(x) = -2x²+1 f(x) = -x²-2 f(x) = (x+2)²arrow_forwardWhat is the vertex, increasing interval, decreasing interval, domain, range, root/solution/zero, and the end behavior?arrow_forwardThe augmented matrix of a linear system has been reduced by row operations to the form shown. Continue the appropriate row operations and describe the solution set of the original system. 1 -1 0 1 -2 00-4 0-6 0 0 1 - 3 3 0 001 4arrow_forward
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