Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN: 9780079039897
Author: Carter
Publisher: McGraw Hill
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Chapter 3.2, Problem 2GP
To determine

To find:

Zero, domain, and range of the given equation y=1202x and to write its mean in the context of given situation.

Expert Solution & Answer
Check Mark

Answer to Problem 2GP

Zero of the equation is x=60 and it means that in 60 minutes, tank will be completely empty, having no air in it.

The domain is {0,1,2,3,,60} and the range is  {0,1,2,3,...,120} . And its zero represents that in 60 minutes, that tank will be completely empty, having no air in it.

Explanation of Solution

Given information:

A person has a 120-CF tank of gas for a 6000 feet dive. The equation y=1202x describes the amount of air in the tank after x minutes.

Concept used:

Zero of an equation is obtained by putting it equal to 0 and then solving it for independent variable x . Also set of all values of x is its domain and set of all values of y is its range.

Calculation:

Plug in y=0 in and solve it for x ,

  0=1202x2x=120x=60

So, only zero of this equation is x=60

  .  

Now x can take values the from 0 to 60 minutes. And accordingly the range as the set of all values of y will be from 0 to 120.

Conclusion:

Value x=60  means that in 60 minutes, tank will be completely empty, having no air in it. So, domain of this relation is {0,1,2,3,,60} and range is  {0,1,2,3,...,120} .

Chapter 3 Solutions

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

Ch. 3.1 - Prob. 2CYUCh. 3.1 - Prob. 3CYUCh. 3.1 - Prob. 4CYUCh. 3.1 - Prob. 5CYUCh. 3.1 - Prob. 6CYUCh. 3.1 - Prob. 7CYUCh. 3.1 - Prob. 8CYUCh. 3.1 - Prob. 9CYUCh. 3.1 - Prob. 10CYUCh. 3.1 - Prob. 11CYUCh. 3.1 - Prob. 12CYUCh. 3.1 - Prob. 13PPSCh. 3.1 - Prob. 14PPSCh. 3.1 - Prob. 15PPSCh. 3.1 - Prob. 16PPSCh. 3.1 - Prob. 17PPSCh. 3.1 - Prob. 18PPSCh. 3.1 - Prob. 19PPSCh. 3.1 - Prob. 20PPSCh. 3.1 - Prob. 21PPSCh. 3.1 - Prob. 22PPSCh. 3.1 - Prob. 23PPSCh. 3.1 - Prob. 24PPSCh. 3.1 - Prob. 25PPSCh. 3.1 - Prob. 26PPSCh. 3.1 - Prob. 27PPSCh. 3.1 - Prob. 28PPSCh. 3.1 - Prob. 29PPSCh. 3.1 - Prob. 30PPSCh. 3.1 - Prob. 31PPSCh. 3.1 - Prob. 32PPSCh. 3.1 - Prob. 33PPSCh. 3.1 - Prob. 34PPSCh. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 36PPSCh. 3.1 - Prob. 37PPSCh. 3.1 - Prob. 38PPSCh. 3.1 - Prob. 39PPSCh. 3.1 - Prob. 40PPSCh. 3.1 - Prob. 41PPSCh. 3.1 - Prob. 42PPSCh. 3.1 - Prob. 43PPSCh. 3.1 - Prob. 44PPSCh. 3.1 - Prob. 45PPSCh. 3.1 - Prob. 46PPSCh. 3.1 - Prob. 47PPSCh. 3.1 - Prob. 48PPSCh. 3.1 - Prob. 49PPSCh. 3.1 - 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