Chapter 30, Problem 63A

To determine

To Explain:

Nuclear reaction for beta decay of $Kr$ .

Answer to Problem 63A

The nuclear reaction for beta decay of $Kr$ is $Kr\to e+\overline{\nu }+Rb$ .

Explanation of Solution

Introduction:

Beta decay is radioactive decay which results in the emission of beta ray from a nucleus of an atom. In the process of beta decay the proton which is present in the nucleus is converted into neutron and this takes place vice versa. If there is transformation of proton to neutron, then it is called as Beta $\left(\beta \right)$ decay.

In the reaction of $Kr$ Beta decay takes place. Beta decay is given by the equation,

  $X{}_N\to Y_{N\pm 1}+e^{\pm }+\overline{v}$ Where,

  $e^{\pm }$ is called positron or an electron,

  $\overline{v}$ is called antineutrino

  $X{}_N$ is called parent nucleus.

  $Y_{N\pm 1}$ is called daughter nucleus

When, Krypton $Kr$ undergoes beta decay isotope, Rubidium $Rb$ is produced and the electrons and antineutrino particles are released. Thus, the equation can be written as,

  $Kr\to e+\overline{\nu }+Rb$

Conclusion:

Hence, the nuclear reaction for beta decay of $Kr$ is $Kr\to e+\overline{\nu }+Rb$ .