Chapter 30, Problem 2STP

To determine

To Choose: The correct option.

Answer to Problem 2STP

Option $B$ is correct option.

Explanation of Solution

Introduction:

Beta decay occurs when the nucleus has large number of neutrons and among one of the proton is converted into other. Beta particles are electrons or positrons.

In the given Reaction, $Pb\to Bi+e^{-}+\overline{\nu }$

The lead $Pb$ undergoes radioactive decay and leads to the formation of bismuth isotope $Bi$ . There is emission of beta particles $\left(\beta \right)$ when the lead undergoes the decay. Also anti-neutrino is produced.

Conclusion:

Thus, option $B$ is the correct option.