Chapter 30, Problem 8STP

To determine

To Choose: The correct option.

Answer to Problem 8STP

Option B

Explanation of Solution

Given:

A positron and electron annihilate to produce gamma energy.

Energy equivalent of mass of an electron, $E=0.51\text{eV}$

Formula Used:

From mass energy relationship:

  $E=m{c}^2$

Here, m is the mass and c is the speed of light.

Calculations:

A positron and electron annihilate to produce gamma energy. It can be represented as follows:

  $e^{-}+e^{+}\to 2\gamma$

This means the energy equivalent mass of both electron and positron would be emitted which is: $2\times 0.51\text{eV= 1}\text{.02 eV}$

Conclusion:

Thus, option B is correct.