Chapter 30, Problem 98A

To determine

To calculate:

The magnetic induction of field.

Answer to Problem 98A

The magnetic induction of field is $0.005\text{Tesla}$ .

Explanation of Solution

Given:

For a wire,

Length of wire $0.10\text{m}$

EMF $=2.0\text{mV}$

Velocity $\text{=4}\text{.0}\text{m/s}$

Wire is moving perpendicular $\left(\sin \theta =1\right)$

Formula Used:

Formula to calculate the magnetic induction of field is given by,

  $EMF=Blv\left(\sin \theta \right)$

Where,

  $EMF$: Electromagnetic induction

  $l$ : Length

  $v$ : Velocity

  $B$ : Magnetic field of induction

Calculation:

Formula for EMF is given by

  $EMF=Blv\left(\sin \theta \right)$

Re-arranging the formula to find Magnetic field $B$ .

  $B=\frac{Emf}{Lv}$

Substituting all the values in the given formula,$\begin{array}{l}B=\frac{Emf}{Lv}=\frac{0.0020}{0.10\times 4.0}=0.005\text{Tesla}\\ =0.005\text{Tesla}\end{array}$

Conclusion:

Hence, the magnetic induction of field is $0.005\text{Tesla}$ .