Chapter 30, Problem 86A

a.

To determine

To Explain:

To complete the equation,

  $N+He\to$

Answer to Problem 86A

The secondary particle emitted by the nucleus for $N+He\to$ is $F$ .

Explanation of Solution

Introduction:

The process of formation of one or more nuclides undergoing collision between two nuclei or between one nucleus and a subatomic particle is called as a nuclear reaction.

An alpha particle consists of two protons and two neutrons that are all held together by the same strong nuclear force binding the nucleus of any atom.

When nitrogen $N$ combines with helium $He$ , it leads to formation of fluorine $F$ .

The secondary particle emitted by the nucleus for $N+He\to$ is $F$ .

Conclusion:

Hence, the secondary particle emitted by the nucleus for $N+He\to$ is $F$ .

b.

To determine

To Explain:

To complete the equation,

  $Al+He\to$

Answer to Problem 86A

The secondary particle emitted by the nucleus for $Al+He\to$ is $P$ .

Explanation of Solution

Introduction:

The process of formation of one or more nuclides undergoing collision between two nuclei or between one nucleus and a subatomic particle is called as a nuclear reaction.

An alpha particle consists of two protons and two neutrons that are all held together by the same strong nuclear force binding the nucleus of any atom.

When aluminum $Al$ combines with helium isotope $He$ , it leads to formation of phosphorus $P$ .

The secondary particle emitted by the nucleus for $Al+He\to$ is $P$ .

Conclusion:

Hence, the secondary particle emitted by the nucleus f for $Al+He\to$ is $P$ .