Mixing SbCl 3 and GaCl 3 in a 1 : 1 molar ratio (using liquid sulfur dioxide as a solvent) gives a solid ionic compound of empirical formula GaSbCl 6 . A controversy arises over whether this compound is ( SbCl 2 + ) ( GaCl 4 − ) or ( GaCl 2 + ) ( SbCl 4 − ) . (a) Predict the molecular structures of the two anions. (b) It is learned that the cation in the compound has a bent structure. Based on this fact, which formulation is more likely to be correct?
Mixing SbCl 3 and GaCl 3 in a 1 : 1 molar ratio (using liquid sulfur dioxide as a solvent) gives a solid ionic compound of empirical formula GaSbCl 6 . A controversy arises over whether this compound is ( SbCl 2 + ) ( GaCl 4 − ) or ( GaCl 2 + ) ( SbCl 4 − ) . (a) Predict the molecular structures of the two anions. (b) It is learned that the cation in the compound has a bent structure. Based on this fact, which formulation is more likely to be correct?
Solution Summary: The author explains how the molecular structures of SbCl_ 4- and
Mixing
SbCl
3
and
GaCl
3
in a
1
:
1
molar ratio (using liquid sulfur dioxide as a solvent) gives a solid ionic compound of empirical formula
GaSbCl
6
. A controversy arises over whether this compound is
(
SbCl
2
+
)
(
GaCl
4
−
)
or
(
GaCl
2
+
)
(
SbCl
4
−
)
.
(a) Predict the molecular structures of the two anions.
(b) It is learned that the cation in the compound has a bent structure. Based on this fact, which formulation is more likely to be correct?
Using Benzene as starting materid show
how each of the Following molecules Contel
Ve syntheswed
CHI
9.
b
-50311
с
CHY
503H
Ночто
d.
อ
•NOV
e
11-0-650
NO2
The molecule PYRIDINE,
6th electrons and is therefore aromatre
and is Assigned the Following structure
contering
Since aromatk moleculoy undergo electrophilic
anomatic substitution, Pyridine shodd undergo
The Following reaction
+ HNO3
12504
a. write all of the possible Mononitration Products
that could Result From this reaction
18. Bared upon the reaction mechanison determime
which of these producty would be the major
Product of the hegetion
a. Explain Why electron withdrawing groups
tend to be meta-Directors. Your answer Should
lyclude all apropriate. Resonance contributing
Structures
fo. Explain why -ll is an outho -tura
drccton even though chlorine has a very High
Electronegativity
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