Concept explainers
(a)
Interpretation:
Lewis diagram of
Concept Introduction:
The valence-shell electron-pair repulsion (VSEPR) theory states that each atom in a molecule occupy a geometry which reduces the repulsions between electrons in the valence shell of that atom. Geometry can be predicted looking at the Lewis structure of the molecule and its steric number.
Polar molecules have a net dipole moment and net dipole moment is zero in nonpolar molecules.
(b)
Interpretation:
Lewis diagram of
Concept Introduction:
The valence-shell electron-pair repulsion (VSEPR) theory states that each atom in a molecule occupy a geometry which reduces the repulsions between electrons in the valence shell of that atom. Geometry can be predicted looking at the Lewis structure of the molecule and its steric number.
Polar molecules have a net dipole moment and net dipole moment is zero in nonpolar molecules.
(c)
Interpretation:
Lewis diagram of
Concept Introduction:
The valence-shell electron-pair repulsion (VSEPR) theory states that each atom in a molecule occupy a geometry which reduces the repulsions between electrons in the valence shell of that atom. Geometry can be predicted looking at the Lewis structure of the molecule and its steric number.
Polar molecules have a net dipole moment and net dipole moment is zero in nonpolar molecules.
(d)
Interpretation:
Lewis diagram of
Concept Introduction:
The valence-shell electron-pair repulsion (VSEPR) theory states that each atom in a molecule occupy a geometry which reduces the repulsions between electrons in the valence shell of that atom. Geometry can be predicted looking at the Lewis structure of the molecule and its steric number.
Polar molecules have a net dipole moment and net dipole moment is zero in nonpolar molecules.
(e)
Interpretation:
Lewis diagram of
Concept Introduction:
The valence-shell electron-pair repulsion (VSEPR) theory states that each atom in a molecule occupy a geometry which reduces the repulsions between electrons in the valence shell of that atom. Geometry can be predicted looking at the Lewis structure of the molecule and its steric number.
Polar molecules have a net dipole moment and net dipole moment is zero in nonpolar molecules.
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Chapter 3 Solutions
Principles of Modern Chemistry
- (a) Methane (CH4) and the perchlorate ion (ClO4- ) are bothdescribed as tetrahedral. What does this indicate about theirbond angles? (b) The NH3 molecule is trigonal pyramidal, while BF3 is trigonal planar. Which of these molecules is flat?arrow_forwardPredict the molecular geometries and draw Lewis structures for each of the following. (a) IF5(b) I3−(c) PCl5(d) SeF4(e) ClF3arrow_forwardWhich of these molecules has a linear molecular geometry and the molecule is polar? (A) CO2 (B) Cl2O (C) N2O (D) SO2arrow_forward
- The structure of caffeine is shown below. (a) Complete the Lewis structure. (b) How many pi bonds are present in caffeine? How many sigma bonds? (c) Identify the hybridization of the carbon atoms. (d) What is the value of the O-C-N angle?arrow_forwardIdentify the electron pair geometry and the molecular structure of each of the following molecules or ions:(a) IF6+(b) CF4(c) BF3(d) SiF5−(e) BeCl2arrow_forwardNitrogen trifluoride (NF3) is used in the electronics industry to clean surfaces. NF3 is also a potent greenhouse gas. (A) Draw the Lewis structure of NF3 and determine its molecular geometry. (B) BF3 and NF3 both have three covalently bonded fluorine atoms around a central atom. Do they have the same dipole moment? (C) Could BF3 also behave as a greenhouse gas? Explain why or why not.arrow_forward
- Consider the reaction BF3 + NH3 -> F3B-NH3 (a) Describe the changes in hybridization of the B and N atoms as a result of this reaction. (b) Describe the shapes of all the reactant molecules with their bond angles. (c) Draw the overall shape of the product molecule and identify the bond angles around B and N atoms. (d) What is the name of the bond between B and N. (e)Describe the bonding orbitals that make the B and F, B and N & N and H bonds in the product molecule.arrow_forwardChemical species are said to be isoelectronic if they have the same Lewis structure (regardless of charge). Consider these ions and write a Lewis structure for a neutral molecule that is isoelectronic with them. (a) CN–, (b) NH4+ (c) CO3 2–arrow_forwardPredict the electron pair geometry and the molecular structure of each of the following molecules or ions:(a) SF6(b) PCl5(c) BeH2(d) CH3+arrow_forward
- 4. (a) Draw the shape of the atomic valence orbitals formed by the overlaping of two fluoride 2p atomic orbitals. (b) Draw the molecular orbital diagrams for F2 and F2*. Identify their bond order and magnetic properties. (c) An unstable nucleus exhibit radioactivity. (i) Explain how the number of protons and neutrons in a radioactive nucleus can be used to predict its probable mode decay. (ii) Illustrate your answer in (i) with a schematic graph.arrow_forwardBorane (BH3) is unstable under normal conditions, but it has been detected at lowpressure.(a) Draw the Lewis structure for borane.(b) Draw a diagram of the bonding in BH3, and label the hybridization of each orbital.(c) Predict the H¬B¬H bond anglearrow_forward. Assume that the third-period element phosphorus forms a diatomic molecule, P2, in an analogous way as nitrogen does to form N2. (a) Write the electronic configuration for P2. Use [Ne2] to represent the electron configuration for the first two periods. (b) Calculate its bond order. (c) What are its magnetic properties (diamagnetic or paramagnetic)?arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning