8th Edition

ISBN: 9781305079113

Author: David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher: Cengage Learning

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Textbook Question

Chapter 3, Problem 19P

HF has equilibrium bond length of 0.926 A ˙ and bond dissociation energy of 565 kJ mol − 1 . Compare the effective potential curve for HF with those for H 2 and F 2 in Problem

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

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Chapter 3, Problem 18P

Chapter 3, Problem 20P

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Chapter 3 Solutions

Principles of Modern Chemistry

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HF has equilibrium bond length of 0.926 A ˙ and bond dissociation energy of 565 kJ mol − 1 . Compare the effective potential curve for HF with those for H 2 and F 2 in Problem

Solution Summary: The author compares the effective potential curve for HF with those for the same and the energy needed to break a chemical bond.

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