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A single-phase
Open-circuit test with the low-voltage terminals excited:
Applied voltage
Short-circuit test with the high-voltage terminals excited:
Applied voltage
Based on the data, compute the efficiency of the autotransformer corresponding to full load, rated voltage, and 0.8 power factor lagging. Comment on why the efficiency is higher as an autotransformer than as a two-winding transformer.
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Chapter 3 Solutions
Power System Analysis and Design (MindTap Course List)
- For the area shown in the figure, write the limits of integration using both the vertical and horizontal cross-sections, then evaluate the integrals. . Find the Fourier expression of the following periodic function 3 -3-2xarrow_forwardI need a solution from an expert without artificial intelligence. Choose the correct answer: 1. In AMI code, the shapes of "1" and "O" are, bit dependent, not related to each other). 2. In FDM the guard band is used to decrease, maintain, not related to). 3. Higher number of levels in PCM produces, (the same, opposite to each other, next the overlap between FDM signals. (increase, (higher quantization error, less number of bits per sample, lower quantization error, the same number of bits per sample). Fe Av 4. If the maximum shift in frequency is 70 kHz and the minimum deviation in frequency of the actual signal is 109.93 MHz, what is the carrier frequency? (110 MHz, 110 kHz, 107 kHz, 102 MHz) 5. TDM of signals requires them to have the same amplitude, sampling frequency, energy). 6. In standard AM, the last step in the transmitter is subtracting, multiplying, dividing). . In digital carrier systems, PSK). (maximum frequency, maximum the carrier signal. (adding, has higher bandwidth.…arrow_forwardNeed Handwritten step by step solution. Do not use chatgpt or AIarrow_forward
- A linear electrical load draws 11 A at a 0.72 lagging power factor./1 153. When a capacitor is connected, the line current dropped to 122 A and the power factor improved to 0.98 lagging. Supply frequency is 50 Hz. a. Let the current drawn from the source before and after introduction of the capacitor be 11 and 12 respectively. Take the source voltage as the reference and express 11 and 12 as vector quantities in polar form. b. Obtain the capacitor current, IC = 12 - 11, graphically as well as using complex number manipulation. Compare the results. c. Express the waveforms of the source current before (11(t)) and after (12(t)) introduction of the capacitor in the form Im sin(2лft + 0). Hand sketch them on the same graph. Clearly label your plots. d. Analytically solve i2(t) – i1(t) using the theories of trigonometry to obtain the capacitor current in the form, ¡C(t) = ICm sin(2πft + OC). Compare the result with the result in Part b.arrow_forwardTransmission line data:Data:• Active power of the load (P): 50 kW• Power factor of the load (PF): 0.8 (lagging)• Line-to-line voltage at the load (V_LC): 13.8 kV• Line resistance (R): 2 Ω• Line inductance (L): 0.8 H• Line capacitance (C): 0.0003 F• Required series compensation: 60% of the line impedance.• Line length: 250 kmDetermine:1. Characteristic impedance and propagation constant.2. The generalized long line constants A, B, C, D.3. Total voltage, current and power at the generating end.4. Voltage regulation.5. Parameters A, B, C, D of the compensation circuit.6. New generalized constants of the power system afterseries compensation.7. Conclusion of the results obtained.arrow_forward3.18 In a single-phase half-wave ac-dc converter, the average value of the load current is 1.78 A. If the converter is operated from a 240 V, 50 Hz supply and if the average value of the output voltage is 27% of the maximum possible value, calculate the following, assume the load to be resistive. (a) Load resistance (b) Firing angle (c) Average output voltage (d) The rms load voltage (e) The rms load current (f) DC power (g) AC power (h) Rectifier efficiency (i) Form factor (j) Ripple factorarrow_forward
- Disassemmble In another way f(t) = [sin(200πt) - cos(300πt)]2arrow_forward☑ 口 ☐ : Homework help starts here! Home | bartleby → https://www.bartleby.com Answered: Decompose using relationships 3 S(+) = 50 sin 3 (500πiz) | bartleby ASK AN EXPERT √ MATH SOLVER Decompose using relationships 3 S(+) = 50 sin 3 (500... Steps "Disassemble in another way." f(+)= 50 Sin³ (500+) Step 1 To decompose f(t)=50 Sin³ (500x+), use trigonometric indentity for Sin³ (e) Sin³ (0)- 3 Sin (e)-Sin (30) 4 Step2: Apply indentity to f(t). f(+)= 50 Sin³ (500+) = 50. 3 Sin (500+) - Sin (3*500π+) = 50. = = 12.5 4 3 Sin (500+)-Sin (1500+) 4 [3 Sin (580x+)-Sin (1500x+)] 37.5 Sin (500+)-12.5 Sin (1500π+) final decomposed form is, PM 05:2 19/12/2024 દ ))^ C W E × م اكتب هنا للبحثarrow_forward6) The principal of DIT hire you to design PBAX with 120 phones. Assuming the number of call is 3/hour/line, the average call duration is 4 minutes, and 55% of all call are made external via a T-1 trunk (24 channels) to the PSTN. Determine carried traffic and channel usage.arrow_forward
- Power System Analysis and Design (MindTap Course ...Electrical EngineeringISBN:9781305632134Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. SarmaPublisher:Cengage Learning