Concept explainers
(a)
To find: the domain of the function.
(a)

Answer to Problem 88E
The required domain of the model of population of herd is t≥0
Explanation of Solution
Given information:
The expected population P or the herd can be modelled by the equation P = (10 + 2.7t)/(1 + 0.1t) where t is the time in years since the initial number of elk were released.
Formula used:
P(t)=10+2.7t1+0.1t
Calculation:
To state the domain of the model,
Consider the following model of the population of herd,
P(t)=10+2.7t1+0.1t
To find the domain,
1+0.1t=0t=−10.1t=−10
Since, P (-10) is not defined at t=−10 ,
Then, the model is defined for each value of t≥0
Therefore, required domain of the model of population of herd is t≥0 and the model is valid only after the elk has been released.
Conclusion:
The required domain of the model of population of herd is t≥0
(b)
To find: The initial number of elk in the herd.
(b)

Answer to Problem 88E
The required initial number of elk in the herd is 10
Explanation of Solution
Formula used:
P(t)=10+2.7t1+0.1t
Calculation:
To find the initial number of elk in the herd
Since, the model of the population of herd is;
P(t)=10+2.7t1+0.1t
Then, for the initial number put t=0 the model,
Then,
P(0)=10+2.7(0)1+0.1(0) =10+01+0P(0)=10
Hence, the required initial number of elk in the herd is 10
Conclusion:
The required initial number of elk in the herd is 10
(c)
To find: The expected population.
(c)

Answer to Problem 88E
There is a limit to size the herd and the horizontal asymptote y = 27 is the limit.
Explanation of Solution
Formula used:
P(t)=10+2.7t1+0.1t
Calculation:
To find the limit to size the herd and the expected population,
Since, the model of the population of herd is;
P(t)=10+2.7t1+0.1t
Then, the limit to size the herd is;
limt→∞P(t)=limt→∞10+2.7t1+0.1t =2.70.1limt→∞P(t)=27
Therefore, there is a limit to size the herd and the horizontal asymptote y = 27 is the limit.
Conclusion:
There is a limit to size the herd and the horizontal asymptote y = 27 is the limit.
Chapter 2 Solutions
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
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