Concept explainers
a.
To graph: The
a.

Explanation of Solution
Given:
Following data is given in the form of a table
Time, x | Height, y |
0.00 | 7.99103 |
0.02 | 7.94464 |
0.04 | 7.93615 |
0.06 | 7.89673 |
0.08 | 7.87322 |
0.10 | 7.84443 |
0.12 | 7.80874 |
0.14 | 7.79095 |
0.16 | 7.75392 |
0.18 | 7.64898 |
0.20 | 7.54421 |
0.22 | 7.43125 |
0.24 | 7.30098 |
0.26 | 7.16875 |
0.28 | 7.02674 |
0.30 | 6.83874 |
0.32 | 6.67460 |
0.34 | 6.51484 |
0.36 | 6.26931 |
0.38 | 6.07766 |
0.40 | 5.85357 |
0.42 | 5.59485 |
0.44 | 5.32125 |
0.46 | 5.05561 |
0.48 | 4.76833 |
0.50 | 4.48594 |
Graph:
By using the above data, points and the model can be plotted as
Interpretation:
The graph shows that as the time increases the height of the softball decreases.
b.
To find: The trend in the data.
b.

Explanation of Solution
Given:
The scatter plot of the data
The given graph decreases with time, the softball’s height is decreasing as the time is increasing and it will come to rest at a point where h = 0.
c.
To find: The quadratic model for the data
c.

Explanation of Solution
Given: Data in the form of table
Calculation:
The quadratic regression for the data is given by
d.
To graph: The points and the regression model on the same graph.
d.

Explanation of Solution
Given: Data in the form of table
Graph:
Interpretation:
As most of the points lie on the regression curve, thus the model can be said as the good fit.
e.
To find: The time when the ball will hit the ground.
e.

Explanation of Solution
Given:
The quadratic model for the problem is given by:
Calculation:
By putting the value of y = 0, the time at which the ball will hit can be found out.
Putting y = 0 in
We have,
Therefore,
Which will give two values of x ,
On simplifying
As the value of x cannot be negative, thus x = 0.75.
Therefore, the time taken for the softball to hit the ground in about 0.75 seconds
Chapter 2 Solutions
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
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