Concept explainers
(a)
To calculate: The zeros of polynomial.
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 36CR
The interval are (-3,-2) and (2, 3)
Explanation of Solution
Given information:
Calculation:
Intermediate value theorem states that if a continuous function takes two values say
By this theorem we can say that if at one point the function is having a positive value and at other point it is having a negative value then between those intervals have a zero of the polynomial.
The table for the polynomial
x | F(x) |
-3 | + |
-2 | - |
-1 | - |
0 | - |
1 | - |
2 | - |
3 | + |
The interval are (-3,-2) and (2.3)
(b)
To calculate: zeros of the polynomial to nearest thousand.
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 36CR
The zeros of polynomial are: - 2.570 and 2.570.
Explanation of Solution
Given information:
The interval are (-3,-2) and (2,3)
Calculation:
Adjusting the interval by 0.1, 0.01 and 0.001
x | F(x) |
-2.5 | - |
-2.6 | + |
x | F(x) |
-2.57 | - |
-2.58 | + |
x | f(x) |
-2.570 | - |
-2.571 | + |
So one zero of polynomial is -2.570
Similarly for the interval (2, 3) the other zero is 2.570.
Chapter 2 Solutions
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
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